`Na_(2)S+H_(2)SO_(4)("Conc.")to S darr+SO_(2)+Na_(2)SO_(4)`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To solve the given reaction \( \text{Na}_2\text{S} + \text{H}_2\text{SO}_4 \,(\text{Conc.}) \rightarrow \text{S} + \text{SO}_2 + \text{Na}_2\text{SO}_4 \), we will analyze the oxidation states of the elements involved and determine the type of reaction.

### Step 1: Identify the oxidation states of each element in the reactants and products.

1. **For \( \text{Na}_2\text{S} \)**:
- Sodium (Na) has an oxidation state of +1.
- Sulfur (S) has an oxidation state of -2.

2. **For \( \text{H}_2\text{SO}_4 \)**:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
- To find the oxidation state of sulfur (S):
- Let the oxidation state of sulfur be \( x \).
- The equation is: \( 2(+1) + x + 4(-2) = 0 \)
- Solving gives \( x = +6 \).

3. **For the products**:
- **Sulfur (S)**: In elemental form, the oxidation state is 0.
- **For \( \text{SO}_2 \)**:
- Oxygen (O) has an oxidation state of -2.
- Let the oxidation state of sulfur be \( y \).
- The equation is: \( y + 2(-2) = 0 \)
- Solving gives \( y = +4 \).
- **For \( \text{Na}_2\text{SO}_4 \)**:
- Sodium (Na) is +1, Oxygen (O) is -2, and sulfur (S) is +6 (same as in \( \text{H}_2\text{SO}_4 \)).

### Step 2: Determine the changes in oxidation states.

- In \( \text{Na}_2\text{S} \):
- Sulfur changes from -2 to 0 (oxidation).

- In \( \text{H}_2\text{SO}_4 \):
- Sulfur changes from +6 to +4 (reduction).

### Step 3: Classify the reaction.

Since one species (sulfur in \( \text{Na}_2\text{S} \)) is oxidized and another species (sulfur in \( \text{H}_2\text{SO}_4 \)) is reduced, this reaction is classified as a **redox reaction**.

### Step 4: Determine the type of redox reaction.

This reaction involves two different reactants undergoing oxidation and reduction, which classifies it as an **intermolecular redox reaction**. It is not a disproportionation reaction (where a single species is both oxidized and reduced) or a comproportionation reaction (where a single species in two different oxidation states reacts).

### Conclusion

The correct classification for the reaction \( \text{Na}_2\text{S} + \text{H}_2\text{SO}_4 \rightarrow \text{S} + \text{SO}_2 + \text{Na}_2\text{SO}_4 \) is that it is an **intermolecular redox reaction**.

---