`NaNO_(3)+H_(2)SO_(4)(Conc.) overset(Hot) to Na_(2)SO_(4)+NO_(2)uarr+O_(2)uarr`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To analyze the reaction \( \text{NaNO}_3 + \text{H}_2\text{SO}_4 \) (conc.) \( \xrightarrow{\text{Hot}} \text{Na}_2\text{SO}_4 + \text{NO}_2 \uparrow + \text{O}_2 \uparrow \), we will determine the type of reaction by examining the oxidation states of the elements involved.

### Step-by-Step Solution:

1. **Identify Reactants and Products**:
- Reactants: Sodium nitrate (\( \text{NaNO}_3 \)) and concentrated sulfuric acid (\( \text{H}_2\text{SO}_4 \)).
- Products: Sodium sulfate (\( \text{Na}_2\text{SO}_4 \)), nitrogen dioxide (\( \text{NO}_2 \)), and oxygen gas (\( \text{O}_2 \)).

2. **Determine Oxidation States**:
- In \( \text{NaNO}_3 \):
- Sodium (\( \text{Na} \)): +1
- Oxygen (\( \text{O} \)): -2
- Let \( x \) be the oxidation state of nitrogen (\( \text{N} \)):
\[ +1 + x + 3(-2) = 0 \implies x - 6 + 1 = 0 \implies x = +5 \]
- Thus, nitrogen in \( \text{NaNO}_3 \) is +5.

- In \( \text{H}_2\text{SO}_4 \):
- Hydrogen: +1
- Oxygen: -2
- Sulfur (\( \text{S} \)): +6 (calculated similarly).

- In \( \text{Na}_2\text{SO}_4 \):
- Sodium: +1
- Sulfur: +6
- Oxygen: -2.

- In \( \text{NO}_2 \):
- Let \( y \) be the oxidation state of nitrogen:
\[ y + 2(-2) = 0 \implies y - 4 = 0 \implies y = +4 \]
- Thus, nitrogen in \( \text{NO}_2 \) is +4.

- In \( \text{O}_2 \):
- Oxygen is in its elemental form, so the oxidation state is 0.

3. **Analyze Changes in Oxidation States**:
- Nitrogen changes from +5 in \( \text{NaNO}_3 \) to +4 in \( \text{NO}_2 \) (reduction).
- Oxygen changes from -2 in \( \text{H}_2\text{SO}_4 \) to 0 in \( \text{O}_2 \) (oxidation).

4. **Determine the Type of Reaction**:
- Since there is a decrease in oxidation state for nitrogen (reduction) and an increase in oxidation state for oxygen (oxidation), this reaction is classified as a **redox reaction**.
- Additionally, since heat is involved (the reaction is performed hot), it is also classified as a **thermal reaction**.

5. **Conclusion**:
- The reaction is a **thermal redox reaction**.