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Mn(OH)(2)+H(2)SO(4) to MnSO(4)+2H(2)O...

`Mn(OH)_(2)+H_(2)SO_(4) to MnSO_(4)+2H_(2)O`

A

For coloured ppt./Black ppt

B

For coloured solution.

C

for clear/colourless solution

D

For white ppt.

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To solve the question regarding the reaction between manganese(II) hydroxide, \( \text{Mn(OH)}_2 \), and sulfuric acid, \( \text{H}_2\text{SO}_4 \), we need to analyze the products formed and determine their characteristics. The reaction is given as: \[ \text{Mn(OH)}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{MnSO}_4 + 2\text{H}_2\text{O} \] ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reactants are manganese(II) hydroxide \( \text{Mn(OH)}_2 \) and sulfuric acid \( \text{H}_2\text{SO}_4 \). - The products are manganese(II) sulfate \( \text{MnSO}_4 \) and water \( 2\text{H}_2\text{O} \). 2. **Analyze the Products**: - Water \( 2\text{H}_2\text{O} \) is known to be a colorless liquid. - Now, we need to analyze manganese(II) sulfate \( \text{MnSO}_4 \). 3. **Determine the Oxidation State of Manganese**: - In \( \text{MnSO}_4 \), the sulfate ion \( \text{SO}_4^{2-} \) has an oxidation state of -2. - To maintain electrical neutrality, manganese must have an oxidation state of +2. 4. **Find the Electronic Configuration of Manganese**: - The atomic number of manganese (Mn) is 25. Its electronic configuration is \( \text{[Ar]} 3d^5 4s^2 \). - For \( \text{Mn}^{2+} \), two electrons are removed, typically from the 4s orbital first. Thus, the configuration becomes \( 3d^5 \). 5. **Check for Unpaired Electrons**: - In the \( 3d^5 \) configuration, all five electrons are unpaired (one in each of the five d orbitals). - The presence of unpaired electrons indicates that \( \text{MnSO}_4 \) can undergo d-d transitions, which are responsible for color. 6. **Conclusion on the Color of the Solution**: - Since \( \text{MnSO}_4 \) has unpaired electrons, it will impart color to the solution. - Therefore, \( \text{MnSO}_4 \) is a colored solution. 7. **Final Answer**: - Among the given options, the correct answer is that the product \( \text{MnSO}_4 \) is a colored solution.
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Knowledge Check

  • Given below are the two reactions of H_(2)O_(2) . Mark the correct statement which follows. (i) 2KMnO_(4) + 3H_(2)SO_(4) + 5H_(2)O_(2) to K_(2)SO_(4) + 2MnSO_(4) + 8H_(2)O + 5O_(2) (ii) 2Cr(OH)_(3) + 4NaOH + 3H_(2)O_(2) to 2Na_(2)CrO_(4) + 8H_(2)O

    A
    (i) Show oxidising nature of `H_(2)O_(2)` and (ii) shows reducing nature of `H_(2)O_(2)`.
    B
    In (i) `H_(2)O_(2)` acts as a reducing agent and in (ii) it acts as an oxidising agent.
    C
    In both (i) and (ii), `H_(2)O_(2)` acts as an oxidising agent.
    D
    In both (i) and (ii), `H_(2)O_(2)` acts as a reducing agent.
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