`Mn(OH)_(2)+H_(2)SO_(4) to MnSO_(4)+2H_(2)O`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between manganese(II) hydroxide, \( \text{Mn(OH)}_2 \), and sulfuric acid, \( \text{H}_2\text{SO}_4 \), we need to analyze the products formed and determine their characteristics. The reaction is given as:

\[ \text{Mn(OH)}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{MnSO}_4 + 2\text{H}_2\text{O} \]

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are manganese(II) hydroxide \( \text{Mn(OH)}_2 \) and sulfuric acid \( \text{H}_2\text{SO}_4 \).
- The products are manganese(II) sulfate \( \text{MnSO}_4 \) and water \( 2\text{H}_2\text{O} \).

2. **Analyze the Products**:
- Water \( 2\text{H}_2\text{O} \) is known to be a colorless liquid.
- Now, we need to analyze manganese(II) sulfate \( \text{MnSO}_4 \).

3. **Determine the Oxidation State of Manganese**:
- In \( \text{MnSO}_4 \), the sulfate ion \( \text{SO}_4^{2-} \) has an oxidation state of -2.
- To maintain electrical neutrality, manganese must have an oxidation state of +2.

4. **Find the Electronic Configuration of Manganese**:
- The atomic number of manganese (Mn) is 25. Its electronic configuration is \( \text{[Ar]} 3d^5 4s^2 \).
- For \( \text{Mn}^{2+} \), two electrons are removed, typically from the 4s orbital first. Thus, the configuration becomes \( 3d^5 \).

5. **Check for Unpaired Electrons**:
- In the \( 3d^5 \) configuration, all five electrons are unpaired (one in each of the five d orbitals).
- The presence of unpaired electrons indicates that \( \text{MnSO}_4 \) can undergo d-d transitions, which are responsible for color.

6. **Conclusion on the Color of the Solution**:
- Since \( \text{MnSO}_4 \) has unpaired electrons, it will impart color to the solution.
- Therefore, \( \text{MnSO}_4 \) is a colored solution.

7. **Final Answer**:
- Among the given options, the correct answer is that the product \( \text{MnSO}_4 \) is a colored solution.