`Cr(OH)_(3) darr+NH_(3)(Excess) to [Cr(NH_(3))_(6)]^(3+)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction of chromium(III) hydroxide with excess ammonia, we can break it down into clear steps:

### Step 1: Identify the Reactants
The reactants in the reaction are chromium(III) hydroxide, Cr(OH)₃, and ammonia, NH₃.

### Step 2: Determine the Reaction Type
This reaction is a complexation reaction where ammonia acts as a ligand and coordinates with the chromium ion.

### Step 3: Write the Reaction
The reaction can be written as:
\[ \text{Cr(OH)}_3 + 6 \text{NH}_3 \rightarrow [\text{Cr(NH}_3)_6]^{3+} + 3 \text{OH}^- \]

### Step 4: Analyze the Products
The product formed is the complex ion \([\text{Cr(NH}_3)_6]^{3+}\).

### Step 5: Determine Solubility
Since the complex ion is soluble in water, it will not form a precipitate. Instead, it will remain in solution.

### Step 6: Identify the Color of the Product
The complex \([\text{Cr(NH}_3)_6]^{3+}\) is known to be purple in color.

### Step 7: Conclusion
Based on the analysis, the reaction will result in a colored solution due to the formation of the purple complex ion.

### Final Answer
The reaction will yield a colored solution.

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