`NiCl_(2)+NH_(3)(excess)to [Ni(NH_(3))_(6)]^(2+)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction of NiCl₂ with excess NH₃ to form the complex [Ni(NH₃)₆]²⁺, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are Nickel(II) chloride (NiCl₂) and ammonia (NH₃).

### Step 2: Determine the Reaction Type
This reaction is a coordination complex formation where ammonia acts as a ligand that coordinates with the Nickel ion.

### Step 3: Write the Reaction
The balanced chemical reaction can be represented as:
\[ \text{NiCl}_2 + 6 \text{NH}_3 \rightarrow [\text{Ni(NH}_3)_6]^{2+} + 2 \text{Cl}^- \]

### Step 4: Analyze the Product
The product formed is [Ni(NH₃)₆]²⁺, which is a coordination complex.

### Step 5: Determine the Solubility and Color of the Product
The complex [Ni(NH₃)₆]²⁺ is soluble in water and does not form a precipitate. Instead, it forms a colored solution.

### Step 6: Identify the Color of the Solution
The color of the [Ni(NH₃)₆]²⁺ complex is violet.

### Conclusion
Based on the analysis, the reaction results in a colored solution due to the formation of the violet complex [Ni(NH₃)₆]²⁺.

### Final Answer
The answer to the question is that the reaction forms a **colored solution**.

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