`2KI+FeCl_(2) to`No reaction.

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between potassium iodide (KI) and iron(II) chloride (FeCl₂), we need to analyze the components and their properties.

### Step-by-Step Solution:

1. **Identify Reactants**: The reactants in the equation are potassium iodide (KI) and iron(II) chloride (FeCl₂).

2. **Understand the Nature of Reactants**:
- KI is a soluble salt that dissociates in water to form K⁺ and I⁻ ions. Potassium ions (K⁺) are colorless, and iodide ions (I⁻) are also colorless.
- FeCl₂ dissociates in water to form Fe²⁺ and Cl⁻ ions. The iron(II) ions (Fe²⁺) are responsible for the color in the solution.

3. **Check for Possible Reactions**:
- When KI and FeCl₂ are mixed, we look for possible double displacement reactions. However, since both reactants are soluble and there is no formation of a precipitate or gas, we expect no visible reaction.

4. **Determine the Color of the Solution**:
- The Fe²⁺ ions impart a color to the solution. In solution, Fe²⁺ ions can exhibit a pale green color due to d-d transitions in the presence of unpaired electrons.

5. **Conclusion on Reaction**:
- Since there is no formation of a precipitate, and the solution remains colored due to the presence of Fe²⁺ ions, we conclude that the reaction does not produce any new solid products or gases.

6. **Select the Correct Option**:
- The correct option is that the solution remains colored due to the presence of Fe²⁺ ions, which indicates that the reaction does not produce a precipitate but results in a colored solution.

### Final Answer:
The correct answer is that there is **No Reaction**, and the solution remains colored due to Fe²⁺ ions.

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