`BaSO_(3)darr+SO_(2)+H_(2)O to Ba(HSO_(3))_(2)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To analyze the reaction given and determine the characteristics of the resulting solution, we can follow these steps:

### Step 1: Identify the Reactants and Products
The reaction provided is:
\[ \text{BaSO}_3 + \text{SO}_2 + \text{H}_2\text{O} \rightarrow \text{Ba(HSO}_3\text{)}_2 \]

Here, the reactants are:
- Barium sulfite (\( \text{BaSO}_3 \))
- Sulfur dioxide (\( \text{SO}_2 \))
- Water (\( \text{H}_2\text{O} \))

The product is:
- Barium hydrogen sulfite (\( \text{Ba(HSO}_3\text{)}_2 \))

### Step 2: Analyze the Reactants
Barium sulfite (\( \text{BaSO}_3 \)) is a precipitate, as indicated by the downward arrow in the reaction. This means it is typically insoluble in water.

### Step 3: Analyze the Product
Barium hydrogen sulfite (\( \text{Ba(HSO}_3\text{)}_2 \)) is known to be soluble in water. This means that when it forms, it will not precipitate out of the solution.

### Step 4: Determine the Appearance of the Solution
Since \( \text{Ba(HSO}_3\text{)}_2 \) is soluble, it will form a solution rather than a precipitate. To further analyze the solution's appearance, we need to consider the color of the product.

### Step 5: Conclusion on the Solution's Appearance
Barium hydrogen sulfite (\( \text{Ba(HSO}_3\text{)}_2 \)) is colorless when dissolved in water. Therefore, the resulting solution from the reaction will be colorless.

### Final Answer
The solution formed from the reaction will be a **colorless solution**.

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