`CrCl_(3)("solution")+ZnSO_(4)("Solution")to`No reaction

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To determine the outcome of the reaction between CrCl₃ solution and ZnSO₄ solution, we need to analyze the properties of the compounds involved and understand why no reaction occurs.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are Chromium(III) chloride (CrCl₃) and Zinc sulfate (ZnSO₄).

2. **Check for Possible Reactions**:
- In general, when two ionic compounds are mixed in solution, a reaction may occur if there is a formation of a precipitate, a gas, or a weak electrolyte. In this case, we need to check if any of these conditions are met.

3. **Analyze the Compounds**:
- **CrCl₃**: Chromium has an oxidation state of +3 in CrCl₃. The electronic configuration of chromium (atomic number 24) is [Ar] 3d⁵ 4s¹. When it loses three electrons (to form Cr³⁺), the configuration becomes [Ar] 3d³. The presence of unpaired electrons in the d-orbitals indicates that CrCl₃ is a colored compound.
- **ZnSO₄**: Zinc has an oxidation state of +2 in ZnSO₄. The electronic configuration of zinc (atomic number 30) is [Ar] 3d¹⁰ 4s². When it loses two electrons (to form Zn²⁺), the configuration becomes [Ar] 3d¹⁰. All electrons in the d-orbitals are paired, which means ZnSO₄ is colorless.

4. **Determine the Color of the Solution**:
- When CrCl₃ (colored) is mixed with ZnSO₄ (colorless), the resulting solution will be colored due to the presence of Cr³⁺ ions.

5. **Conclusion on Reaction**:
- Since there is no formation of a precipitate or gas, and both reactants remain in solution without any observable change, we conclude that there is no reaction.

6. **Final Answer**:
- The correct option is that the solution remains colored due to the presence of Cr³⁺ ions, and there is no reaction.