`Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between sodium chromate (Na₂CrO₄) and hydrochloric acid (HCl) to form dichromic acid (H₂Cr₂O₇) and sodium sulfate (Na₂SO₄), we will follow these steps:

### Step 1: Identify the Reactants and Products
- The reactants in this reaction are sodium chromate (Na₂CrO₄) and hydrochloric acid (HCl).
- The products formed are dichromic acid (H₂Cr₂O₇) and sodium sulfate (Na₂SO₄).

### Step 2: Determine the Solubility of the Reactants and Products
- Sodium chromate (Na₂CrO₄) is soluble in water.
- Hydrochloric acid (HCl) is also soluble in water.
- Dichromic acid (H₂Cr₂O₇) is soluble in water.
- Sodium sulfate (Na₂SO₄) is soluble in water.

### Step 3: Analyze the Reaction for Precipitate Formation
- Since all the reactants and products are soluble in water, there will be no formation of a precipitate in this reaction. Thus, options indicating a precipitate can be eliminated.

### Step 4: Identify the Color of the Products
- H₂Cr₂O₇ (dichromic acid) is known to have a dark red color when dissolved in water.
- Therefore, the solution formed from this reaction will be colored due to the presence of H₂Cr₂O₇.

### Step 5: Conclusion
- Since the reaction produces a dark red solution, the answer to the question is that it forms a colored solution.

### Final Answer
The reaction of Na₂CrO₄ with HCl produces a colored solution due to the formation of H₂Cr₂O₇, which is dark red.

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