`MnSO_(4)+Sr(NO_(3))_(2) to SrSO_(4) darr`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between MnSO₄ and Sr(NO₃)₂, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Manganese(II) sulfate (MnSO₄)
- Strontium nitrate (Sr(NO₃)₂)

### Step 2: Write the Reaction
The reaction can be written as:
\[ \text{MnSO}_4 + \text{Sr(NO}_3\text{)}_2 \rightarrow \text{SrSO}_4 + \text{Mn(NO}_3\text{)}_2 \]

### Step 3: Determine the Products
From the reaction, we can see that strontium sulfate (SrSO₄) is formed as a product. The other product formed will be manganese(II) nitrate (Mn(NO₃)₂).

### Step 4: Analyze the Formation of Precipitate
The question asks whether the reaction forms a colored solution, a clear solution, or a precipitate.
- Strontium sulfate (SrSO₄) is known to be insoluble in water and forms a precipitate.

### Step 5: Identify the Color of the Precipitate
The color of strontium sulfate (SrSO₄) is white. Therefore, we can conclude that the precipitate formed in this reaction is white.

### Step 6: Eliminate Other Options
Since we have established that a precipitate is formed, we can eliminate options that suggest a colored solution or a clear solution. The only viable option left is that a white precipitate is formed.

### Final Answer
The reaction between MnSO₄ and Sr(NO₃)₂ produces a white precipitate of SrSO₄.

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