`(NH_(4))_(2)SO_(4)+Sr(OH)_(2) to SrSO_(4)darr+2NH_(3)uarr`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between ammonium sulfate \((NH_4)_2SO_4\) and strontium hydroxide \(Sr(OH)_2\), we need to analyze the products formed and their characteristics.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are ammonium sulfate \((NH_4)_2SO_4\) and strontium hydroxide \(Sr(OH)_2\).

2. **Write the Reaction**:
The reaction can be written as:
\[ (NH_4)_2SO_4 + Sr(OH)_2 \rightarrow SrSO_4 + 2NH_3 \]

3. **Identify the Products**:
The products of the reaction are strontium sulfate \(SrSO_4\) and ammonia \(NH_3\).

4. **Determine the State of the Products**:
- Ammonia \(NH_3\) is a gas, as indicated by the upward arrow in the reaction.
- Strontium sulfate \(SrSO_4\) is known to be insoluble in water, and it forms a precipitate, indicated by the downward arrow.

5. **Identify the Color of the Precipitate**:
Strontium sulfate \(SrSO_4\) is a white solid. Therefore, the precipitate formed in this reaction is white.

6. **Conclusion**:
Since we have established that a white precipitate is formed (from \(SrSO_4\)), the answer to the question is that the reaction produces a white precipitate.

### Final Answer:
The reaction produces a **white precipitate**.

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