`underset(("Coloured solution"))(P)+BaCl_(2) to underset(("White"))(Qdarr)+underset(("Coloured solution"))(R)` ltBrgt Then salt 'P' in above reaction is:

Options

A. `Na_(2)CrO_(4)`
B. `ZnSO_(4)`
C. `CuSO_(4)`
D. `AgNO_(3)`

Explanation

To determine the salt 'P' in the given reaction, we need to analyze the information provided step by step.

### Step 1: Understand the Reaction
The reaction states that a colored solution (P) reacts with BaCl₂ to produce a white precipitate (Q) and another colored solution (R).

### Step 2: Identify Possible Candidates for P
We need to find a colored solution that reacts with BaCl₂. Some common colored solutions include:
- Sodium Chromate (Na₂CrO₄) - Yellow
- Copper(II) Sulfate (CuSO₄) - Blue
- Zinc Sulfate (ZnSO₄) - Colorless

### Step 3: Analyze Each Candidate
1. **Sodium Chromate (Na₂CrO₄)**:
- Reaction: Na₂CrO₄ + BaCl₂ → BaCrO₄ (Yellow precipitate) + NaCl (Colorless solution)
- Result: This does not satisfy our requirement because BaCrO₄ is a precipitate, not a solution.

2. **Zinc Sulfate (ZnSO₄)**:
- Reaction: ZnSO₄ + BaCl₂ → BaSO₄ (White precipitate) + ZnCl₂ (Colorless solution)
- Result: This also does not satisfy our requirement as both products are not colored solutions.

3. **Copper(II) Sulfate (CuSO₄)**:
- Reaction: CuSO₄ + BaCl₂ → BaSO₄ (White precipitate) + CuCl₂ (Blue solution)
- Result: This satisfies our requirement because CuCl₂ is a colored solution (blue) and BaSO₄ is a white precipitate.

### Step 4: Conclusion
From the analysis, the only candidate that satisfies the conditions of the reaction is Copper(II) Sulfate (CuSO₄). Therefore, the salt 'P' in the reaction is:

**Answer: Copper(II) Sulfate (CuSO₄)**

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