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Which of the following combination doen'...

Which of the following combination doen's evolve `Cl_(2)` gas?

A

`HCl(aq.)+KMnO_(4)`

B

`HCl+MnO_(2)`

C

`HCl+I_(2)`

D

`HCl+F_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which combination does not evolve chlorine gas, we will analyze each of the given reactions step by step. ### Step 1: Analyze the first combination - Hydrochloric acid (HCl) and Potassium Permanganate (KMnO4) **Reaction:** \[ \text{HCl} + \text{KMnO}_4 \rightarrow \text{KCl} + \text{MnCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \] **Observation:** In this reaction, chlorine gas (Cl2) is produced as a product. ### Step 2: Analyze the second combination - Hydrochloric acid (HCl) and Manganese Dioxide (MnO2) **Reaction:** \[ \text{HCl} + \text{MnO}_2 \rightarrow \text{MnCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \] **Observation:** Here too, chlorine gas (Cl2) is evolved. ### Step 3: Analyze the third combination - Hydrochloric acid (HCl) and Iodine (I2) **Reaction:** \[ \text{HCl} + \text{I}_2 \rightarrow \text{No Reaction} \] **Observation:** In this case, there is no reaction between hydrochloric acid and iodine. Therefore, chlorine gas is not evolved. ### Step 4: Analyze the fourth combination - Hydrochloric acid (HCl) and Chlorine (Cl2) **Reaction:** \[ \text{HCl} + \text{Cl}_2 \rightarrow \text{HCl} + \text{Cl}_2 \] **Observation:** This reaction involves chlorine gas, and it does not produce any new chlorine gas but involves it in the reaction. ### Conclusion Among the combinations analyzed, the only one that does not evolve chlorine gas is the reaction between hydrochloric acid and iodine. **Final Answer:** The combination that does not evolve Cl2 gas is the reaction between Hydrochloric Acid and Iodine (Option C). ---

To determine which combination does not evolve chlorine gas, we will analyze each of the given reactions step by step. ### Step 1: Analyze the first combination - Hydrochloric acid (HCl) and Potassium Permanganate (KMnO4) **Reaction:** \[ \text{HCl} + \text{KMnO}_4 \rightarrow \text{KCl} + \text{MnCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \] **Observation:** ...
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