Which of the following combination does not liberated `NH_(3)` gas?

Options

A. Heating of `NH_(4)ClO_(4)`
B. Heating of `NH_(4)Cl`
C. `(NH_(4))_(2)CO_(30+NaOH`
D. `Li_(3)N+H_(2)O`

Explanation

To determine which combination does not liberate NH3 gas, we will analyze each option provided in the question step by step.

### Step 1: Analyze the first option - Heating of NH4ClO4
- When NH4ClO4 is heated, it undergoes thermal decomposition.
- The reaction can be represented as:
\[ \text{NH}_4\text{ClO}_4 \xrightarrow{\text{heat}} \text{N}_2 + \text{Cl}_2 + 2 \text{O}_2 + 4 \text{H}_2\text{O} \]
- In this reaction, nitrogen gas (N2) and water (H2O) are produced, but no ammonia (NH3) is formed.

### Step 2: Analyze the second option - Heating of NH4Cl
- When NH4Cl is heated, the reaction is:
\[ \text{NH}_4\text{Cl} \xrightarrow{\text{heat}} \text{NH}_3 + \text{HCl} \]
- Here, ammonia (NH3) gas is liberated along with hydrochloric acid (HCl).

### Step 3: Analyze the third option - NH4 whole twice CO3 plus NaOH
- The reaction between ammonium carbonate (NH4)2CO3 and sodium hydroxide (NaOH) is:
\[ (NH_4)_2\text{CO}_3 + 2 \text{NaOH} \rightarrow 2 \text{NH}_3 + \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} \]
- In this case, ammonia (NH3) gas is also liberated.

### Step 4: Analyze the fourth option - Li3N plus H2O
- The reaction of lithium nitride (Li3N) with water (H2O) is:
\[ \text{Li}_3\text{N} + 3 \text{H}_2\text{O} \rightarrow 3 \text{LiOH} + \text{NH}_3 \]
- Here, ammonia (NH3) gas is produced as well.

### Conclusion
After analyzing all the options, we find that:
- **Option A (Heating of NH4ClO4)** does not liberate NH3 gas, while all other options do.

### Final Answer
The combination that does not liberate NH3 gas is **A: Heating of NH4ClO4**.

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