One of the hydrolysed product of the following compound does not react with silica of glass vessel:

Options

A. `BF_(3)`
B. `ClF_(5)`
C. `XeF_(2)`
D. `SF_(4)`

Explanation

To solve the problem, we need to analyze the hydrolysis products of the given compounds and determine which one does not produce HF (hydrofluoric acid), as HF is known to react with silica (SiO2) found in glass vessels.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds given are:
- BF3 (Boron trifluoride)
- ClF5 (Chlorine pentafluoride)
- XCF2 (A hypothetical compound, where X is an unspecified element)
- SF4 (Sulfur tetrafluoride)

2. **Hydrolysis of BF3**:
- When BF3 is hydrolyzed, it reacts with water to form boric acid (H3BO3) and tetrafluoroboric acid (HBF4):
\[ \text{BF3} + 3 \text{H2O} \rightarrow \text{H3BO3} + 3 \text{HF} \]
- However, it is important to note that the product HBF4 does not release HF in the same way.

3. **Hydrolysis of ClF5**:
- ClF5 upon hydrolysis produces HF:
\[ \text{ClF5} + 2 \text{H2O} \rightarrow \text{HCl} + 5 \text{HF} \]
- This means HF is produced, which can react with silica.

4. **Hydrolysis of XCF2**:
- Similarly, XCF2 when hydrolyzed also produces HF:
\[ \text{XCF2} + 2 \text{H2O} \rightarrow \text{HX} + 2 \text{HF} \]
- Again, HF is produced, which can react with silica.

5. **Hydrolysis of SF4**:
- SF4 hydrolyzes to produce HF:
\[ \text{SF4} + 2 \text{H2O} \rightarrow \text{H2S} + 4 \text{HF} \]
- HF is produced, which can react with silica.

6. **Conclusion**:
- Among the compounds analyzed, only BF3 does not produce HF upon hydrolysis. Instead, it produces H3BO3 and HBF4, which do not react with silica.
- Therefore, the answer to the question is **BF3**.

### Final Answer:
The hydrolyzed product of the compound that does not react with silica of glass vessels is **BF3**.

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