`Pb+Dil.HNO_(3) overset(Warm)toP+Quarr+H_(2)O`
Incorrect statement for Q is:

Options

A. Paramagnetic colourless gas
B. It is oxidized to paramagnetic coloured gas by air
C. It combines with `Fe_(2)(SO_(4))_(3)`
D. It can be also obtained by disproportionation of `HNO_(2)`

Answer

To solve the question regarding the reaction of lead (Pb) with dilute nitric acid (HNO3) and to identify the incorrect statement about the product Q (which is nitric oxide, NO), we can follow these steps:

### Step 1: Write the Reaction
The reaction between lead and dilute nitric acid can be represented as:
\[ \text{Pb} + \text{Dil. HNO}_3 \xrightarrow{\text{Warm}} \text{Pb(NO}_3\text{)}_2 + \text{NO} + \text{H}_2\text{O} \]

### Step 2: Identify the Products
From the reaction, we can identify:
- P = Pb(NO3)2 (Lead(II) nitrate)
- Q = NO (Nitric oxide)

### Step 3: Analyze the Properties of Q (NO)
1. **Paramagnetic Nature**:
- NO has an odd number of electrons (11 total: 5 from nitrogen and 6 from oxygen), making it paramagnetic.
- **Statement**: "It is a paramagnetic colorless gas." - This statement is correct.

2. **Oxidation to NO2**:
- NO can be oxidized to nitrogen dioxide (NO2), which is a brown gas.
- **Statement**: "It is oxidized to a paramagnetic colored gas by air." - This statement is also correct.

3. **Reactivity with Iron Compounds**:
- NO can react with ferrous sulfate (FeSO4) but does not react with ferric sulfate (Fe2(SO4)3).
- **Statement**: "It combines with Fe2SO4." - This statement is incorrect.

4. **Disproportionation Reaction**:
- NO can be formed by the disproportionation of nitrous acid (HNO2).
- **Statement**: "It can also be obtained by the disproportionation of HNO2." - This statement is correct.

### Step 4: Conclusion
The incorrect statement regarding Q (NO) is:
- "It combines with Fe2SO4." - This is the incorrect statement.

### Final Answer
The incorrect statement for Q is: "It combines with Fe2SO4."

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