`Pb+Dil.HNO_(3) overset(Warm)toP+Quarr+H_(2)O`
Incorrect statement for Q is:

Options

A. Paramagnetic colourless gas
B. It is oxidized to paramagnetic coloured gas by air
C. It combines with `Fe_(2)(SO_(4))_(3)`
D. It is also obtained by disproportionation of `HNO_(2)`

Explanation

To solve the question regarding the reaction of lead (Pb) with dilute nitric acid (HNO3) and identify the incorrect statement about the product Q (which is nitric oxide, NO), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction of lead (Pb) with dilute nitric acid (HNO3) when warmed can be represented as:
\[ \text{Pb} + \text{Dil. HNO}_3 \xrightarrow{\text{Warm}} \text{Pb(NO}_3\text{)}_2 + \text{NO} + \text{H}_2\text{O} \]
Here, P is Pb(NO3)2, and Q is NO.

2. **Analyze Product Q (NO)**:
- NO (nitric oxide) is the product formed in this reaction.
- It is important to check the properties of NO to determine the incorrect statement.

3. **Evaluate Statements**:
- **Statement 1**: "NO is a paramagnetic colored gas."
- NO is indeed paramagnetic because it has an unpaired electron. However, it is colorless, not colored. Therefore, this statement is partially incorrect.
- **Statement 2**: "NO is oxidized to a paramagnetic colored gas by air."
- This statement is correct. NO can be oxidized to NO2, which is a brown colored gas.
- **Statement 3**: "NO combines with Fe2(SO4)3."
- This statement is incorrect. NO does not react with Fe2(SO4)3 (ferric sulfate). It can react with FeSO4 (ferrous sulfate) but not with Fe2(SO4)3.
- **Statement 4**: "NO can also be obtained by the disproportionation of HNO2."
- This statement is correct. HNO2 can disproportionate to form NO and HNO3.

4. **Identify the Incorrect Statement**:
- After analyzing all statements, the incorrect statement regarding Q (NO) is:
- **Statement 3**: "NO combines with Fe2(SO4)3."

### Final Answer:
The incorrect statement for Q (NO) is that it combines with Fe2(SO4)3.

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