Which combination gives maximum number of products?

Options

A. `P_(4)+SOCl_(2)`
B. `P_(4)+SO_(2)Cl_(2)`
C. `XeF_(4)+H_(2)O`
D. `NH_(4)NO_(3)+Zn+`Excess Excess NaOH

Explanation

To determine which combination gives the maximum number of products, we will analyze each reaction step by step.

### Step 1: Analyze the first reaction (P4 + SOCl2)
- **Reaction**: P4 + SOCl2
- **Products**: PCl3 + SO2 + S2Cl2
- **Total Products**: 3 (PCl3, SO2, S2Cl2)

### Step 2: Analyze the second reaction (P4 + SO2Cl2)
- **Reaction**: P4 + SO2Cl2
- **Products**: PCl5 + SO2
- **Total Products**: 2 (PCl5, SO2)

### Step 3: Analyze the third reaction (XeF4 + H2O)
- **Reaction**: XeF4 + H2O
- **Products**: XeO3 + Xe + O2 + HF
- **Total Products**: 4 (XeO3, Xe, O2, HF)

### Step 4: Analyze the fourth reaction (NH4NO3 + Zn + NaOH)
- **Reaction**: NH4NO3 + Zn + NaOH
- **Products**: NaNO3 + NH3 + H2O
- **Total Products**: 3 (NaNO3, NH3, H2O)

### Conclusion
After analyzing all four reactions:
- First reaction: 3 products
- Second reaction: 2 products
- Third reaction: 4 products (maximum)
- Fourth reaction: 3 products

The combination that gives the maximum number of products is the third reaction (XeF4 + H2O) with a total of 4 products.

### Final Answer
The combination that gives the maximum number of products is **XeF4 + H2O**.

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