`Xe+F_(2) overset(1:20) to X overset(H_(2)O) to Y overset(H_(2)O ) to Z overset(H_(2)O) to XeO_(3)`
Select correct option(s) for X, Y, Z and given chemical change:

Options

A. X, Y and Z are in same oxidation state
B. All have equal number of lone pair on central atom
C. All are non-planar
D. All have equal number of covalent bonds

Explanation

To solve the given question step by step, we need to analyze the chemical reactions and identify the compounds X, Y, and Z formed during the process.

### Step-by-Step Solution:

1. **Identify the Reaction of Xe with F2**:
- The initial reaction is between xenon (Xe) and fluorine (F2) in a 1:20 ratio.
- The product formed from this reaction is **XeF6** (X).

**Hint**: Remember that xenon can form compounds with fluorine, and the ratio indicates the stoichiometry of the reaction.

2. **React X (XeF6) with H2O**:
- When XeF6 is treated with water (H2O), it hydrolyzes to form **XeOF4** (Y).

**Hint**: Hydrolysis reactions often involve the replacement of halogen atoms with hydroxyl groups or oxygen.

3. **React Y (XeOF4) with H2O**:
- Next, treating XeOF4 with water yields **XeO2F2** (Z).

**Hint**: Again, consider how water interacts with the compound, replacing fluorine atoms with hydroxyl groups.

4. **React Z (XeO2F2) with H2O**:
- Finally, when XeO2F2 is treated with water, it produces **XeO3** as the final product.

**Hint**: The final product is a common oxide of xenon, indicating complete hydrolysis.

### Summary of Products:
- **X = XeF6**
- **Y = XeOF4**
- **Z = XeO2F2**

### Verification of Properties:
- **Oxidation States**: All compounds have xenon in the +6 oxidation state.
- **Lone Pairs**: Each compound has one lone pair on the central xenon atom.
- **Geometries**:
- XeF6 has a distorted octahedral geometry.
- XeOF4 has a square pyramidal geometry.
- XeO2F2 has a seesaw geometry.

### Conclusion:
- All compounds are non-planar.
- Each compound has six covalent bonds.

### Final Answer:
- **X = XeF6**
- **Y = XeOF4**
- **Z = XeO2F2**