If hydrolysis of interhalogen compound can be represented by following general reaction:
`XY_(n_(1))overset(water)to n_(1)HY+HXO_(n_(2))`
If given interhalogen compound is polarr and non-planar, then calculate value of `n_(1)+n_(2)`.

Explanation

To solve the problem, we need to analyze the hydrolysis of an interhalogen compound represented by the general reaction:

\[ XY_{n_1} + \text{water} \rightarrow n_1 HY + HXO_{n_2} \]

Where \( n_1 \) and \( n_2 \) are the coefficients we need to determine.

### Step-by-Step Solution:

1. **Identify the Type of Interhalogen Compound**:
- Interhalogen compounds are formed between two different halogens (X and Y).
- The problem states that the interhalogen compound is polar and non-planar.

2. **Determine the Possible Structures**:
- Interhalogen compounds can be of different types based on the number of halogen atoms attached:
- \( XY \)
- \( XY_3 \)
- \( XY_5 \)
- \( XY_7 \)
- Among these, we need to find which ones are polar and non-planar.

3. **Analyze the Geometry**:
- \( XY \) (e.g., ClF) is linear and thus planar.
- \( XY_3 \) (e.g., ClF3) has a bent shape but is not non-planar.
- \( XY_5 \) (e.g., ClF5) has a square pyramidal shape, which is non-planar.
- \( XY_7 \) (e.g., IF7) has a pentagonal bipyramidal shape, which is planar.

Since we need a non-planar and polar compound, \( XY_5 \) is the only suitable candidate.

4. **Write the Hydrolysis Reaction**:
- For \( XY_5 \), when it reacts with water, the hydrolysis can be represented as:
\[ XY_5 + \text{water} \rightarrow 5 HY + HXO_3 \]
- Here, \( n_1 = 5 \) (the number of HY produced) and \( n_2 = 3 \) (the number of HXO produced).

5. **Calculate \( n_1 + n_2 \)**:
- Now, we can find the value of \( n_1 + n_2 \):
\[ n_1 + n_2 = 5 + 3 = 8 \]

### Final Answer:
The value of \( n_1 + n_2 \) is **8**.