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Preparation of looking mirrors involves ...

Preparation of looking mirrors involves the use of :

A

red lead

B

ammonical silver nitrate

C

ammonical `AgNO_(3)`+red lead

D

ammonical `AgNO_(3)`+red lead+HCHO

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The correct Answer is:
To solve the question regarding the preparation of looking mirrors, we need to understand the components involved in the process. The preparation of looking mirrors typically involves the following steps: ### Step-by-Step Solution: 1. **Identify the Components**: The preparation of looking mirrors involves several chemicals. The key components mentioned are: - Ammonical silver nitrate (AgNO3 in ammonia solution) - Red lead (Pb3O4) - Formaldehyde (HCHO) 2. **Role of Ammonical Silver Nitrate**: Ammonical silver nitrate is used to produce silver oxide (Ag2O) when it reacts with sodium hydroxide (NaOH). The reaction is as follows: \[ 2 \text{AgNO}_3 + 2 \text{NaOH} \rightarrow \text{Ag}_2\text{O} + 2 \text{NaNO}_3 + 2 \text{H}_2\text{O} \] This silver oxide is essential for the subsequent reactions. 3. **Formation of Tollen's Reagent**: The silver oxide (Ag2O) then reacts with sodium nitrate (NaNO3) and ammonia (NH3) to form Tollen's reagent: \[ \text{Ag}_2\text{O} + 2 \text{NaNO}_3 + 4 \text{NH}_3 \rightarrow 2 \text{Ag(NH}_3\text{)}_2\text{NO}_3 + \text{NaOH} \] Tollen's reagent is a solution of silver(I) complex that is used to test for aldehydes. 4. **Reaction with Formaldehyde**: When formaldehyde (HCHO) is introduced, it reacts with Tollen's reagent, leading to the reduction of silver ions to metallic silver, which deposits on the surface, forming a mirror: \[ \text{RCHO} + 2 \text{Ag(NH}_3\text{)}_2^+ \rightarrow \text{RCOOH} + 2 \text{Ag} + 2 \text{NH}_3 \] This reaction is what creates the silver mirror effect. 5. **Function of Red Lead**: Red lead (Pb3O4) is used to protect the thin layer of silver from scratches and damage. It is also a cost-effective and readily available material. 6. **Conclusion**: Based on the above reactions and roles of each component, the correct answer to the question is: **Ammonical silver nitrate + Red lead + HCHO** (Option 4). ### Final Answer: The preparation of looking mirrors involves the use of ammonical silver nitrate, red lead, and formaldehyde (HCHO). ---
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VK JAISWAL ENGLISH-d-BLOCK ELEMENTS-ASSERTION-REASON TYPE QUESTIONS
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  3. Cu((aq.))^+ has less stable nature than Cu((aq.))^(2+) but Fe((aq.))^(...

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  4. Assertion: Zn gives H(2) gas with dil. HCl and also with dil. H(2)SO(4...

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  5. Assertion: KMnO(4) has different equivalent wieghts in acid, neutral o...

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  6. Assertion: Cu^(2+) is more stable than Cu^(+) Reason: Electrode pote...

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  7. Statement 1: Concentrated solution of CuCl(2) in water is yellow in co...

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  8. Assertion: KMnO(4) is purple in colour due to charge transfer . Reas...

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  9. Assertion : CrO(3) reacts with HCl to form chromyl chloride gas Reas...

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  10. Mercury is the only metal which is liquid at 0^(@)C. This is due to it...

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  11. Assertion: CuSO(4)*5H(2)O and FeSO(4)*7H(2)O are blue and green colour...

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  12. Assertion: FeSO(4) and Fe(2)(SO(4))(3) undergoes intramolecular redox ...

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  13. Assertion: Zn(OH)(2) is dissolved in both NH(4)OH and NaOH solution Re...

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  14. Assertion: Increasing order of covalent character among given compound...

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  15. Assertion: AgNO(3) reacts with KCN to form white ppt. of AgCN. This wh...

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  16. Assertion: Zero and negative oxidation state of d-block metal ion are ...

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  17. Assertion: Aquated copper(I) cation undergoes disproportionation as: ...

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  18. Assertion: Melting point of Mn is more than that of Fe. Reason : Mn ...

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  19. Assertion: Cu^(2+)(aq) is less than Cu^(3+)(aq) but Fe^(3+) is more st...

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  20. Assertion: Zn gives H(2) gas with dil. HCl and dil. H(2)SO(4) but not...

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  21. Assertion: KMnO(4) has different equivalent wieghts in acid, neutral o...

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