The solubility of silver bromide in hypo solution due to the formation of

Options

A. `Ag_(2)SO_(3)`
B. `Ag_(2)S_(2)O_(3)`
C. `[Ag(S_(2)O_(3))]^(-)`
D. `[Ag(S_(2)O_(3))]^(3-)`

Answer

To solve the question regarding the solubility of silver bromide in hypo solution due to the formation of a specific compound, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Components**:
- The hypo solution is sodium thiosulfate, which has the chemical formula Na2S2O3.

2. **Understand the Reaction**:
- When silver bromide (AgBr) is treated with sodium thiosulfate, a reaction occurs that increases the solubility of silver bromide.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ \text{AgBr (s)} + \text{Na}_2\text{S}_2\text{O}_3 (aq) \rightarrow \text{Na}_3\text{AgS}_2\text{O}_3 (aq) + \text{NaBr} (aq) \]
- Here, solid silver bromide reacts with sodium thiosulfate to form a soluble complex, sodium thiosulfatoargentate (Na3AgS2O3), and sodium bromide (NaBr).

4. **Conclusion**:
- The formation of the soluble complex Na3AgS2O3 is what increases the solubility of silver bromide in the hypo solution.

### Final Answer:
The solubility of silver bromide in hypo solution is due to the formation of sodium thiosulfatoargentate (Na3AgS2O3).

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