Mercury (II) chloride solution on reaction with gaseous ammonia forms:

Options

A. `Hg(NH_(3))Cl*HgO`
B. `Hg(NH_(3))_(2)Cl_(2)`
C. `[Hg(NH_(3))_(2)]Cl_(2)`
D. `[Hg(NH_(3))_(2)]Cl`

Answer

To solve the problem of what mercury (II) chloride solution forms when reacted with gaseous ammonia, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are mercury (II) chloride and gaseous ammonia.
- The chemical formula for mercury (II) chloride is \( \text{HgCl}_2 \).
- The chemical formula for gaseous ammonia is \( \text{NH}_3 \).

2. **Write the Reaction**:
- When mercury (II) chloride reacts with gaseous ammonia, the reaction can be represented as:
\[ \text{HgCl}_2 + \text{NH}_3 \rightarrow \text{Hg(NH}_3\text{)}_2\text{Cl}_2 \]

3. **Product Formation**:
- The product formed from this reaction is a complex salt, which is \( \text{Hg(NH}_3\text{)}_2\text{Cl}_2 \).
- This indicates that two ammonia molecules coordinate with one mercury ion, while two chloride ions are present.

4. **Final Product**:
- Therefore, the final product of the reaction between mercury (II) chloride and gaseous ammonia is:
\[ \text{Hg(NH}_3\text{)}_2\text{Cl}_2 \]

5. **Conclusion**:
- The required product when mercury (II) chloride solution reacts with gaseous ammonia is \( \text{Hg(NH}_3\text{)}_2\text{Cl}_2 \).