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Identify the wrong statement regarding c...

Identify the wrong statement regarding copper sulphate `:`

A

It reacts with KI to give `I_(2)`

B

It reacts with KCl to give `Cl_(2)`

C

It's tartarate complex reacts with NaOH and glucose to give `Cu_(2)O`

D

It gives CuO on strong heating in air

Text Solution

AI Generated Solution

The correct Answer is:
To identify the wrong statement regarding copper sulfate, let's analyze each statement one by one. ### Step 1: Analyze the first statement **Statement:** Copper sulfate reacts with potassium iodide (KI) to liberate iodine gas (I2). **Analysis:** When copper sulfate (CuSO4) reacts with potassium iodide (KI), the reaction can be represented as: \[ \text{CuSO}_4 + 2 \text{KI} \rightarrow \text{Cu}_2\text{I}_2 + \text{I}_2 + \text{K}_2\text{SO}_4 \] This indicates that iodine gas (I2) is indeed liberated during the reaction. **Conclusion:** This statement is **correct**. ### Step 2: Analyze the second statement **Statement:** Copper sulfate reacts with potassium chloride (KCl) to give chlorine gas (Cl2). **Analysis:** When copper sulfate reacts with potassium chloride, the reaction can be represented as: \[ \text{CuSO}_4 + 2 \text{KCl} \rightarrow \text{CuCl}_2 + \text{K}_2\text{SO}_4 \] In this reaction, chlorine gas (Cl2) is **not** produced. **Conclusion:** This statement is **incorrect**. ### Step 3: Analyze the third statement **Statement:** The tartrate complex of copper reacts with NaOH and glucose to give cuprous oxide (Cu2O). **Analysis:** The reaction of the tartrate complex of copper with NaOH and glucose can be represented as: \[ \text{RCHO} + 2 \text{Cu}^{2+} + 5 \text{OH}^- \rightarrow \text{RCOO}^- + \text{Cu}_2\text{O} + 3 \text{H}_2\text{O} \] This indicates that cuprous oxide (Cu2O) is indeed formed. **Conclusion:** This statement is **correct**. ### Step 4: Analyze the fourth statement **Statement:** Copper sulfate gives cupric oxide (CuO) on strong heating in air. **Analysis:** When copper sulfate is heated in air, it decomposes to form cupric oxide (CuO), sulfur dioxide (SO2), and oxygen (O2): \[ 2 \text{CuSO}_4 \rightarrow 2 \text{CuO} + 2 \text{SO}_2 + \text{O}_2 \] This indicates that cupric oxide (CuO) is indeed produced. **Conclusion:** This statement is **correct**. ### Final Conclusion The wrong statement regarding copper sulfate is: - **It reacts with potassium chloride to give chlorine gas (Cl2).**
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