The treatment of zinc with very dilute nitric acid produces:

Options

A. `NO`
B. `N_(2)O`
C. `NO_(2)`
D. `NH_(4)^(+)`

Answer

To solve the question regarding the treatment of zinc with very dilute nitric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are zinc (Zn) and very dilute nitric acid (HNO3).

2. **Understand the Reaction Conditions**:
When zinc reacts with very dilute nitric acid, the concentration of nitric acid is low, which affects the products formed. In contrast, concentrated nitric acid would lead to different products.

3. **Write the Balanced Chemical Equation**:
The reaction of zinc with very dilute nitric acid can be represented as follows:
\[ 4 \text{Zn} + 10 \text{HNO}_3 \rightarrow 4 \text{Zn(NO}_3\text{)}_2 + \text{NH}_4\text{NO}_3 + 3 \text{H}_2\text{O} \]

4. **Identify the Products**:
From the balanced equation, we can see that the products formed are zinc nitrate (Zn(NO3)2), ammonium nitrate (NH4NO3), and water (H2O).

5. **Determine the Key Ion Produced**:
The question specifically asks for what is produced, and from the balanced equation, we can see that ammonium ions (NH4+) are produced as part of ammonium nitrate.

6. **Conclusion**:
Therefore, the treatment of zinc with very dilute nitric acid produces ammonium ions (NH4+).

### Final Answer:
The treatment of zinc with very dilute nitric acid produces NH4+ ions.

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