Dilute nitric acid on reaction with silver liberates:

Options

A. NO gas
B. `NO_(2)` gas
C. `N_(2)` gas
D. `O_(2)` gas

Answer

To solve the question "Dilute nitric acid on reaction with silver liberates:", we can follow these steps:

### Step 1: Understand the Reactants
We have dilute nitric acid (HNO3) and silver (Ag) as our reactants.

### Step 2: Write the Reaction
When silver reacts with dilute nitric acid, it forms silver nitrate (AgNO3), water (H2O), and nitrogen monoxide (NO) as products. The balanced chemical equation for the reaction is:

\[ 3 \text{Ag} + 4 \text{HNO}_3 \rightarrow 3 \text{AgNO}_3 + 2 \text{H}_2\text{O} + \text{NO} \]

### Step 3: Identify the Products
From the balanced equation, we can see that the products of the reaction include silver nitrate (AgNO3), water (H2O), and nitrogen monoxide (NO).

### Step 4: Determine What is Liberated
The question specifically asks what is liberated during the reaction. In this case, the gas that is liberated is nitrogen monoxide (NO).

### Conclusion
Thus, when dilute nitric acid reacts with silver, it liberates nitrogen monoxide (NO).

### Final Answer
**Nitrogen monoxide (NO)** is liberated when dilute nitric acid reacts with silver.

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