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Iron forms iron halides salts by reactin...

Iron forms iron halides salts by reacting the metal directly with halogen. `FeI_(3)` does not exist. `FeF_(3)` is white soled inspite of five unpaired electrons with `d^(5)` configuration . `FeCl_(3)` is soluble in water and is used as a mordant in dyeing industry.
Q.`FeCl_(3)` solution added to `K_(4)[Fe(CN)_(6)]` gives A while with `KSCN` gives B. A and B respectively are:

A

`Fe_(3)[Fe(CN)_(6)]_(2), Fe(CNS)_(3)`

B

`Fe_(4)[Fe(CN)_(6)]_(2), KFe(CNS)_(3)`

C

`Fe_(4)[Fe(CN)_(6)]_(3), K_(3)[Fe(CNS)_(6)]`

D

`Fe_(4)[Fe(CN)_(6)]_(3), K_(3)[Fe(SCN)_(6)]`

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AI Generated Solution

The correct Answer is:
To solve the question regarding the reactions of FeCl₃ with K₄[Fe(CN)₆] and KSCN, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The first reactant is FeCl₃ (iron(III) chloride). - The second reactant is K₄[Fe(CN)₆] (potassium ferrocyanide). - The third reactant is KSCN (potassium thiocyanate). 2. **Reaction of FeCl₃ with K₄[Fe(CN)₆]**: - When FeCl₃ is added to K₄[Fe(CN)₆], a complex compound is formed. - The reaction can be represented as: \[ 4 \text{FeCl}_3 + 3 \text{K}_4[\text{Fe(CN)}_6] \rightarrow \text{Fe}_3[\text{Fe(CN)}_6] + 12 \text{KCl} \] - The resulting complex is known as Prussian Blue, which is a deep blue color. 3. **Identify Compound A**: - The complex formed is called iron(III) hexacyanoferrate(II), and its formula is \(\text{Fe}_3[\text{Fe(CN)}_6]\). - Therefore, Compound A is \(\text{Fe}_3[\text{Fe(CN)}_6]\). 4. **Reaction of FeCl₃ with KSCN**: - When FeCl₃ reacts with KSCN, it forms another complex. - The reaction can be represented as: \[ \text{FeCl}_3 + 3 \text{KSCN} \rightarrow \text{K}_3[\text{Fe(SCN)}_6] + 3 \text{KCl} \] - The resulting complex is a deep red color. 5. **Identify Compound B**: - The complex formed is called potassium thiocyanoferrate(III), and its formula is \(\text{K}_3[\text{Fe(SCN)}_6]\). - Therefore, Compound B is \(\text{K}_3[\text{Fe(SCN)}_6]\). ### Final Answer: - A is \(\text{Fe}_3[\text{Fe(CN)}_6]\) (iron(III) hexacyanoferrate(II)). - B is \(\text{K}_3[\text{Fe(SCN)}_6]\) (potassium thiocyanoferrate(III)).
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VK JAISWAL ENGLISH-d-BLOCK ELEMENTS-Level 3
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