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Choose correct statements (s) regarding ...

Choose correct statements (s) regarding the following reactions.
`Cr_(2)O_(7)^(2-)(aq)+3SO_(3)^(2-)(aq)+8H^(+) rarr 2Cr^(3+)(aq)+3SO_(4)^(2-)(aq)+4H_(2)O`

A

`Cr_(2)O_(7)^(2-)` is oxidising agent

B

`SO_(3)^(2-)` is reducing agent

C

The oxidation number of per 'S' atom in `2SO_(3)^(2-)` is increase by two

D

The oxidation number of per 'Cr' atom in `Cr_(2)O_(7)^(2-)` is decrease by two

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given reaction and determine the correct statements regarding it, we will follow these steps: ### Step 1: Identify the oxidation states of chromium in Cr₂O₇²⁻ and Cr³⁺ - In the dichromate ion (Cr₂O₇²⁻), the oxidation state of chromium (Cr) is +6. - In the product Cr³⁺, the oxidation state of chromium is +3. ### Step 2: Identify the oxidation states of sulfur in SO₃²⁻ and SO₄²⁻ - In the sulfite ion (SO₃²⁻), the oxidation state of sulfur (S) is +4. - In the sulfate ion (SO₄²⁻), the oxidation state of sulfur is +6. ### Step 3: Determine the changes in oxidation states - For chromium: The oxidation state changes from +6 (in Cr₂O₇²⁻) to +3 (in Cr³⁺), which is a decrease of 3. - For sulfur: The oxidation state changes from +4 (in SO₃²⁻) to +6 (in SO₄²⁻), which is an increase of 2. ### Step 4: Identify the roles of the species in the reaction - Since Cr₂O₇²⁻ is reducing the oxidation state of sulfur (from +4 to +6), it is acting as an oxidizing agent. - Since SO₃²⁻ is increasing its oxidation state (from +4 to +6), it is acting as a reducing agent. ### Step 5: Evaluate the correctness of the statements 1. **Statement 1**: Cr₂O₇²⁻ is an oxidizing agent. **(Correct)** 2. **Statement 2**: SO₃²⁻ is a reducing agent. **(Correct)** 3. **Statement 3**: The oxidation state of S atom in SO₃²⁻ increases by 2. **(Correct)** 4. **Statement 4**: The oxidation number of each chromium atom in Cr₂O₇²⁻ decreases by 2. **(Incorrect)** - It decreases by 3. ### Conclusion The correct statements regarding the reaction are: - Cr₂O₇²⁻ is an oxidizing agent. - SO₃²⁻ is a reducing agent. - The oxidation state of S atom in SO₃²⁻ increases by 2. - The statement about the oxidation number of chromium is incorrect.
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