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Assertion: CuSO(4)*5H(2)O and FeSO(4)*7H...

Assertion: `CuSO_(4)*5H_(2)O and FeSO_(4)*7H_(2)O` are blue and green colour compounds respectively.
Reason: Both compounds have their specific colour due to phenomenon of polarisation of anion.

A

If both assertion and reason are true and the reason is the correct explanation of assertion

B

If both assertion and reason are true and the reason is not the correct explanation of assertion

C

If assertion is false but reason is true

D

If assertion is true but the reason is false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and reason statements provided: ### Step 1: Analyze the Assertion - The assertion states that `CuSO4·5H2O` (copper(II) sulfate pentahydrate) is a blue compound and `FeSO4·7H2O` (iron(II) sulfate heptahydrate) is a green compound. - **Copper(II) sulfate** has a blue color due to the presence of unpaired electrons in its d-orbitals, which allows for d-d transitions. - **Iron(II) sulfate** appears green due to its own electronic configuration, which also allows for d-d transitions with unpaired electrons. ### Conclusion for Step 1: - The assertion is **true** because both compounds are indeed colored as stated. ### Step 2: Analyze the Reason - The reason provided states that the specific colors of both compounds are due to the phenomenon of polarization of the anion. - Polarization refers to the distortion of the electron cloud of an anion by a cation. However, the color of transition metal compounds is primarily due to the presence of unpaired electrons and the d-d transitions that occur, not due to polarization of the anion. ### Conclusion for Step 2: - The reason is **false** because the color is not due to polarization but rather due to d-d transitions involving unpaired electrons. ### Final Conclusion: - The assertion is true, but the reason is false. Therefore, the correct answer is that the assertion is true, but the reason is false. ### Summary of Steps: 1. **Assertion Analysis**: Confirmed that both `CuSO4·5H2O` and `FeSO4·7H2O` are colored due to unpaired electrons. 2. **Reason Analysis**: Determined that polarization of the anion does not explain the color of these compounds.
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