Assertion: `Zn(OH)_(2)` is dissolved in both `NH_(4)OH` and NaOH solution Reason- NaOH and `NH_(4)OH` being basic can dissolve amphoteric `Zn(OH)_(2)`.

Options

A. If both assertion and reason are true and the reason is the correct explanation of assertion
B. If both assertion and reason are true and the reason is not the correct explanation of assertion
C. If assertion is false but reason is true
D. If assertion is true but the reason is false

Answer

To solve the question, we will analyze both the assertion and the reason provided, and determine their validity step by step.

### Step 1: Understanding the Assertion
The assertion states that Zn(OH)₂ (zinc hydroxide) is dissolved in both NH₄OH (ammonium hydroxide) and NaOH (sodium hydroxide) solutions.

- **Fact Check**: Zinc hydroxide is known to be amphoteric, meaning it can react with both acids and bases. While it is insoluble in water, it can dissolve in strong bases like NaOH and NH₄OH.
- **Conclusion**: The assertion is **true** because Zn(OH)₂ does dissolve in both NaOH and NH₄OH.

### Step 2: Understanding the Reason
The reason states that NaOH and NH₄OH, being basic, can dissolve amphoteric Zn(OH)₂.

- **Fact Check**: While it is true that NaOH and NH₄OH are basic, the reason provided implies that any basic solution can dissolve amphoteric compounds. This is misleading because not all basic solutions can dissolve all amphoteric compounds. The dissolution of Zn(OH)₂ specifically occurs because it reacts to form soluble zincate ions (Zn(OH)₄²⁻) when hydroxide ions are present in excess.
- **Conclusion**: The reason is **false** because it overgeneralizes the behavior of amphoteric compounds in basic solutions.

### Final Conclusion
- The assertion is **true**.
- The reason is **false**.

### Answer
Thus, the correct answer is that the assertion is true, but the reason is false.

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