The gaseous product(s) expected at room temperature by reaction of sodium borohydride and boron trifluoride under anhydrous conditions is/are:

Options

A. `H_(2)`
B. `B_(2)H_(6) and H_(2)`
C. `B_(2)H_(6)`
D. `BH_(2)F and H_(2)`

Answer

To solve the question regarding the gaseous product(s) expected from the reaction of sodium borohydride (NaBH4) and boron trifluoride (BF3) under anhydrous conditions, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Sodium borohydride: NaBH4
- Boron trifluoride: BF3

### Step 2: Write the Reaction
When sodium borohydride reacts with boron trifluoride, the reaction can be represented as:
\[ NaBH_4 + BF_3 \rightarrow B_2H_6 + NaF \]

### Step 3: Analyze the Products
From the reaction, we can see that one of the products is diborane (B2H6), which is known to be a gaseous compound at room temperature. The other product, sodium fluoride (NaF), is a solid.

### Step 4: Determine the Gaseous Product
Since we are specifically looking for gaseous products, we conclude that:
- The gaseous product formed from the reaction is diborane (B2H6).

### Conclusion
Thus, the gaseous product expected at room temperature from the reaction of sodium borohydride and boron trifluoride under anhydrous conditions is diborane (B2H6).

### Final Answer
The correct answer is: **B2H6 (diborane)**.

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