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H(2)C(2)O(4)overset(triangle)to"gas"(A)+...

`H_(2)C_(2)O_(4)overset(triangle)to"gas"(A)+"gas"(B)+"liquid"(C)`. Gas(A) burns with a blue flame and is oxidised to gas(B).
`"Gas"(A)+Cl_(2)toDtooverset(NH_(3),triangle)toE`
A,B,C,D and E are

A

`CO_(2),Co,H_(2)O,HCONH_(2)`

B

`CO,CO_(2),CoCl_(2),HCONH_(2)`

C

`CO,CO_(2),H_(2)O,COCl_(2),NH_(2)CONH_(2)`

D

`CO,CO_(2),H_(20O,COCl_(2)`

Text Solution

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The correct Answer is:
To solve the question step by step, we will analyze the decomposition of oxalic acid (H₂C₂O₄) and identify the gases and liquids produced during the reaction, as well as the subsequent reactions involving these products. ### Step 1: Identify the decomposition products of oxalic acid (H₂C₂O₄) When oxalic acid is heated, it decomposes to form: - **Gas A** - **Gas B** - **Liquid C** The decomposition reaction can be represented as: \[ \text{H}_2\text{C}_2\text{O}_4 \xrightarrow{\Delta} \text{Gas A} + \text{Gas B} + \text{Liquid C} \] ### Step 2: Determine the nature of Gas A It is given that Gas A burns with a blue flame and is oxidized to Gas B. A gas that burns with a blue flame is typically carbon monoxide (CO), which is known for its blue flame during combustion. ### Step 3: Identify Gas B Gas B is the product of the oxidation of Gas A (CO). When carbon monoxide is oxidized, it forms carbon dioxide (CO₂). Therefore, we can conclude: - **Gas A = Carbon monoxide (CO)** - **Gas B = Carbon dioxide (CO₂)** ### Step 4: Identify Liquid C During the decomposition of oxalic acid, water (H₂O) is also produced as a liquid. Therefore: - **Liquid C = Water (H₂O)** ### Step 5: Reaction of Gas A with Chlorine (Cl₂) Gas A (CO) reacts with chlorine gas (Cl₂) to form a compound D. The reaction is: \[ \text{CO} + \text{Cl}_2 \rightarrow \text{D} \] The product of this reaction is phosgene (COCl₂). ### Step 6: Reaction of Compound D with Ammonia (NH₃) Compound D (phosgene) reacts with ammonia when heated to form compound E. The reaction can be represented as: \[ \text{COCl}_2 + 2\text{NH}_3 \rightarrow \text{E} \] The product of this reaction is urea (NH₂CONH₂). ### Summary of the Identified Compounds - **Gas A = Carbon monoxide (CO)** - **Gas B = Carbon dioxide (CO₂)** - **Liquid C = Water (H₂O)** - **Compound D = Phosgene (COCl₂)** - **Compound E = Urea (NH₂CONH₂)** ### Final Answer Thus, the final identification of A, B, C, D, and E is: - A = Carbon monoxide (CO) - B = Carbon dioxide (CO₂) - C = Water (H₂O) - D = Phosgene (COCl₂) - E = Urea (NH₂CONH₂)
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