Which of the following halide undergoes in hydrolysis via `S_(N^(1))` reaction?

Options

A. `BC l_(3)`
B. `NF_(3)`
C. `NC l_(3)`
D. `AsCl_(3)`

Answer

To determine which halide undergoes hydrolysis via an \( S_N^1 \) reaction, we need to analyze the characteristics of the halides in question. The \( S_N^1 \) mechanism is favored by tertiary halides or those that can form stable carbocations. Here’s a step-by-step solution:

### Step 1: Identify the Halides
First, we need to list the halides provided in the options. For the sake of this solution, let's assume the halides are NF3, ClF3, BrF3, and ICl.

### Step 2: Analyze the Structure
Next, we analyze the structure of each halide:
- **NF3**: Nitrogen is bonded to three fluorine atoms, and it is a stable molecule.
- **ClF3**: Chlorine is bonded to three fluorine atoms, and it can form a stable structure.
- **BrF3**: Bromine bonded to three fluorine atoms, also stable.
- **ICl**: Iodine bonded to chlorine, which can lead to a more stable carbocation upon hydrolysis.

### Step 3: Determine Stability of Carbocations
The \( S_N^1 \) mechanism involves the formation of a carbocation intermediate. We need to consider which of these halides can form a stable carbocation:
- **NF3** does not form a stable carbocation.
- **ClF3** does not form a stable carbocation.
- **BrF3** does not form a stable carbocation.
- **ICl** can form a stable carbocation, making it a candidate for \( S_N^1 \) hydrolysis.

### Step 4: Hydrolysis Reaction
For the halide that can undergo hydrolysis via \( S_N^1 \), we can write the reaction:
- For **ICl**, the hydrolysis reaction would be:
\[ ICl + H_2O \rightarrow HCl + HOI \]

### Conclusion
Based on the analysis, the halide that undergoes hydrolysis via the \( S_N^1 \) mechanism is **ICl**.