Amphilbole silicate structure has 'x' number of corner shared per tetrahedron. The value of x is :

Options

A. 2
B. `2(1)/(2)`
C. 3
D. 4

Explanation

To solve the problem regarding the number of corner-shared tetrahedra in the amphibole silicate structure, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Amphibole Silicates**:
- Amphibole silicates are a group of silicate minerals that have a double chain structure. They consist of tetrahedra (SiO4) units linked together.

2. **Drawing the Structure**:
- To visualize the amphibole structure, we can represent the tetrahedra as triangles (since they are 3D shapes, we simplify them in 2D for understanding).
- Each tetrahedron consists of a silicon atom (Si) at the center and four oxygen atoms (O) at the corners.

3. **Identifying Corner Sharing**:
- In the amphibole structure, tetrahedra share corners (oxygen atoms) with adjacent tetrahedra.
- For each tetrahedron, we need to determine how many oxygen atoms are shared with neighboring tetrahedra.

4. **Counting Shared Oxygen Atoms**:
- Typically, in the amphibole structure, each tetrahedron shares three of its oxygen atoms with neighboring tetrahedra.
- This means that for every tetrahedron, three corners (oxygen atoms) are shared with adjacent tetrahedra.

5. **Calculating the Value of 'x'**:
- Since each tetrahedron shares three oxygen atoms, we can conclude that the value of 'x' (the number of corner-shared tetrahedra per tetrahedron) is 3.
- Therefore, the answer to the question is: **x = 3**.

### Final Answer:
The value of 'x' in the amphibole silicate structure is **3**.

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