Nitrozen (i) oxide is produced by

Options

A. thermal decomposition of sodium nitrite at low temperature
B. thermal decomposition of ammonium nitrite
C. disproportionation of `N_(2)O_(4)`
D. interaction of hydroxyl amine and nitrous acid

Answer

To determine how nitrogen (I) oxide is produced, we can analyze the options given and the relevant chemical reactions involved. Here’s a step-by-step solution:

### Step 1: Identify the Options
The options provided are:
1. Thermal decomposition of sodium nitrite at low temperature.
2. Thermal decomposition of ammonium nitrite.
3. Disproportionation of N2O4.
4. Interaction of hydroxylamine and nitrous acid.

### Step 2: Analyze Each Option
- **Option 1: Thermal decomposition of sodium nitrite at low temperature**
Sodium nitrite (NaNO2) decomposes to produce sodium nitrate (NaNO3) and nitrogen oxides, but typically not nitrogen (I) oxide (N2O).

- **Option 2: Thermal decomposition of ammonium nitrite**
Ammonium nitrite (NH4NO2) decomposes to produce nitrogen gas (N2) and water (H2O), not nitrogen (I) oxide.

- **Option 3: Disproportionation of N2O4**
The disproportionation of dinitrogen tetroxide (N2O4) produces nitrogen dioxide (NO2) and nitrogen monoxide (NO), but it does not directly yield nitrogen (I) oxide.

- **Option 4: Interaction of hydroxylamine and nitrous acid**
Hydroxylamine (NH2OH) reacts with nitrous acid (HNO2) to form hyponitrous acid (H2N2O2) and water. The nitrogen in hyponitrous acid has an oxidation state of +1, which corresponds to nitrogen (I) oxide.

### Step 3: Write the Reaction
The reaction can be represented as:
\[ \text{NH}_2\text{OH} + \text{HNO}_2 \rightarrow \text{H}_2\text{N}_2\text{O}_2 + \text{H}_2\text{O} \]

### Step 4: Determine the Oxidation State
In hyponitrous acid (H2N2O2):
- Let the oxidation state of nitrogen be \( x \).
- The equation for the oxidation state can be set up as follows:
\[ 2x + 2(-2) + 2(1) = 0 \]
Simplifying this gives:
\[ 2x - 4 + 2 = 0 \implies 2x - 2 = 0 \implies 2x = 2 \implies x = 1 \]
Thus, the oxidation state of nitrogen in hyponitrous acid is +1.

### Conclusion
Based on the analysis, nitrogen (I) oxide is produced by the interaction of hydroxylamine and nitrous acid. Therefore, the correct answer is **Option 4**.

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