Incorrect statement about `PH_(3)` is:

Options

A. it is produced by hydrolysis of `Ca_(3)P_(2)`
B. It gives black ppt. `(Cu_(3)P_(2))` with `CuSO_(4)` solution
C. Spontaneously burnns in presence of `P_(2)H_(4)`
D. it does not react with `B_(2)H_(6)`

Explanation

To determine the incorrect statement about phosphine (PH₃), let's analyze each statement provided:

### Step 1: Analyze the first statement
**Statement 1:** "PH₃ is produced by hydrolysis of Ca₃P₂."

- **Explanation:** When calcium phosphide (Ca₃P₂) undergoes hydrolysis, it reacts with water to produce phosphine (PH₃) and calcium hydroxide (Ca(OH)₂). The balanced reaction is:
\[ Ca_3P_2 + 6H_2O \rightarrow 2PH_3 + 3Ca(OH)_2 \]
- **Conclusion:** This statement is **correct**.

### Step 2: Analyze the second statement
**Statement 2:** "PH₃ gives a black precipitate with CuSO₄ solution."

- **Explanation:** When phosphine (PH₃) reacts with copper(II) sulfate (CuSO₄), it forms copper phosphide (Cu₃P₂), which is a black precipitate, along with sulfuric acid (H₂SO₄). The balanced reaction is:
\[ 3CuSO_4 + 2PH_3 \rightarrow Cu_3P_2 + 3H_2SO_4 \]
- **Conclusion:** This statement is **correct**.

### Step 3: Analyze the third statement
**Statement 3:** "PH₃ spontaneously burns in presence of P₂H₄."

- **Explanation:** P₂H₄ (diphosphene) is an impurity that can cause phosphine to burn in air. Pure phosphine (PH₃) does not burn spontaneously in air, but the presence of P₂H₄ can lead to combustion.
- **Conclusion:** This statement is **correct**.

### Step 4: Analyze the fourth statement
**Statement 4:** "PH₃ does not react with B₂H₆."

- **Explanation:** This statement is incorrect because phosphine (PH₃) does react with diborane (B₂H₆) to form a complex known as ammonia borane. The reaction can be represented as:
\[ PH_3 + B_2H_6 \rightarrow (BH_3) \cdot (PH_3) \text{ (complex)} \]
- **Conclusion:** This statement is **incorrect**.

### Final Answer
The incorrect statement about PH₃ is:
**"PH₃ does not react with B₂H₆."**

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