Predict the correct product when `Cl_(2)` passed through `H-overset(18)(O)-overset(18)(O)-H` solution.

Options

A. `H^(+)+Cl^(-)+O_(2)` (both oxygen having 18)
B. HOCl and `HClO_(2)` (all oxygen having 18)
C. `HClO_(4)` and HCl (all oxygen having 18)
D. `Cl_(2)O and H_(2)O` (all oxygen having 18)

Answer

To predict the correct product when \( Cl_2 \) is passed through \( H_2^{18}O \) solution, we can follow these steps:

### Step 1: Identify the Reactants
We have chlorine gas (\( Cl_2 \)) and hydrogen peroxide (\( H_2O_2 \)), where the oxygen atoms are specifically labeled as \( ^{18}O \).

### Step 2: Understand the Reaction
When chlorine gas reacts with hydrogen peroxide, the general reaction can be represented as:
\[ Cl_2 + H_2O_2 \rightarrow HCl + O_2 \]
In this reaction, chlorine reacts with hydrogen peroxide to produce hydrochloric acid (HCl) and oxygen gas (O2).

### Step 3: Consider the Isotopes
Since we are using \( H_2^{18}O \), the oxygen in the products will also contain the \( ^{18}O \) isotope. Therefore, when \( H_2O_2 \) decomposes in the presence of \( Cl_2 \), the oxygen produced will also be \( ^{18}O \).

### Step 4: Write the Products
From the reaction, we can deduce that:
- The products will include \( HCl \) (which consists of \( H^+ \) and \( Cl^- \)) and \( O_2 \) (which will consist of \( O^{18} \) due to the initial reactants).

### Step 5: Finalize the Reaction
Thus, the complete balanced reaction can be summarized as:
\[ Cl_2 + H_2^{18}O_2 \rightarrow 2 HCl + O_2^{18} \]
However, since we are interested in the products, we can simplify it to:
\[ H^+ + Cl^- + O_2^{18} \]

### Conclusion
The correct product when \( Cl_2 \) is passed through \( H_2^{18}O \) solution is:
\[ H^+ + Cl^- + O_2^{18} \]