The three elements X,Y and Z with electronic configuration shown below al form hydrides:
`{:("Element","Electronic configuration"),(X,1s^(2)2s^(2)2p^(2)),(Y,1s^(2)2s^(2)2p^(6)3s^(1)),(Z,1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(10)4s^(2)4p^(5)):}`
Which set of properties match correctly with properties of the hydrides of these elements:

Options

A. Hydride of X- Colourless gas insoluble in `H_(2)O`, Hydride of Y-Silver/grey solid reacts with `H_(2)O` to form an alkali
Hydride of Z-Colourless gas forms a strong acid in `H_(2)O`
B. Hydride of X-Colourless liquid, no reaction with `H_(2)O`, Hydride of Y-Silver/grey solid forms `H_(2) and H_(2)O`, Hydride of Z-Ionic solid with formula ZH
C. Hydride of X-Non-polar compound reacts with `Cl_(2)` in light, Hydride of Y-Silver/grey ionic solid with formula `YH_(2)`,Hydride of Z-Forms when water is added to phosphorus and elemental Z.
D. Hydride of X-Colourless gas which burns with air, Hydride of Y-Silver/grey solid which reacts violently with acids, Hydride of Z-Colourless, corrosive liquid at STP

Explanation

To solve the question regarding the properties of the hydrides formed by the elements X, Y, and Z based on their electronic configurations, we will follow these steps:

### Step 1: Identify the Elements
1. **Element X**: The electronic configuration is \(1s^2 2s^2 2p^2\).
- This indicates it is in the second period and belongs to group 14 (p-block).
- Therefore, **Element X is Carbon (C)**.

2. **Element Y**: The electronic configuration is \(1s^2 2s^2 2p^6 3s^1\).
- This indicates it is in the third period and belongs to group 1 (s-block).
- Therefore, **Element Y is Sodium (Na)**.

3. **Element Z**: The electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^5\).
- This indicates it is in the fourth period and belongs to group 17 (p-block).
- Therefore, **Element Z is Bromine (Br)**.

### Step 2: Identify the Hydrides
1. **Hydride of X (Carbon)**: The hydride formed is **Methane (CH₄)**.
2. **Hydride of Y (Sodium)**: The hydride formed is **Sodium Hydride (NaH)**.
3. **Hydride of Z (Bromine)**: The hydride formed is **Hydrogen Bromide (HBr)**.

### Step 3: Analyze the Properties of the Hydrides
1. **Methane (CH₄)**:
- It is a colorless gas.
- It is insoluble in water (nonpolar).

2. **Sodium Hydride (NaH)**:
- It is a silver-gray solid.
- It reacts with water to form sodium hydroxide (NaOH), which is an alkali.

3. **Hydrogen Bromide (HBr)**:
- It is a colorless gas.
- It forms a strong acid (H₃O⁺) when dissolved in water.

### Step 4: Match Properties with Hydrides
Now we will check the given options against the properties identified:

1. **Option 1**:
- Hydride of X: Colorless gas, insoluble in H₂O (Correct for CH₄).
- Hydride of Y: Silver-gray solid, reacts with H₂O to form an alkali (Correct for NaH).
- Hydride of Z: Colorless gas, forms a strong acid in H₂O (Correct for HBr).
- **Conclusion**: This option is correct.

2. **Option 2**:
- Hydride of X: Colorless liquid, no reaction with water (Incorrect, CH₄ is a gas).
- **Conclusion**: This option is incorrect.

3. **Option 3**:
- Hydride of Y: Silver-gray ionic solid with formula YS₂ (Incorrect, the formula for sodium hydride is NaH).
- **Conclusion**: This option is incorrect.

4. **Option 4**:
- Hydride of Z: Colorless corrosive liquid at STP (Incorrect, HBr is a gas at room temperature).
- **Conclusion**: This option is incorrect.

### Final Answer
The correct set of properties that match with the hydrides of the elements is **Option 1**.

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