`XeF_(6)` dissolves in anhydrous HF to give a good conducting solution which contains:

Options

A. `H^(+) and XeF_(7)^(-)` ion
B. `HF_(2)^(-) and XeF_(5)^(+)` ions
C. `HXeF_(6)^(+) and F^(-)` ions
D. none of these

Explanation

To solve the question regarding the dissolution of xenon hexafluoride (XeF₆) in anhydrous hydrogen fluoride (HF) and the resulting conductive solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Compounds**:
- Xenon hexafluoride (XeF₆) is a colorless solid that sublimes into yellow vapors and is known to be a strong fluorinating agent.
- Anhydrous hydrogen fluoride (HF) is a colorless, acidic, and highly corrosive compound.

2. **Dissolution Process**:
- When XeF₆ is dissolved in anhydrous HF, a reaction occurs where one of the fluorine atoms from XeF₆ interacts with HF.
- The interaction leads to the formation of ions in the solution.

3. **Ion Formation**:
- In this process, XeF₆ can lose one fluorine atom to form a positively charged ion, which is xenon pentafluoride (XeF₅⁺).
- The fluorine atom that is lost from XeF₆ combines with HF to form the bifluoride ion (HF₂⁻).

4. **Resulting Ions**:
- Therefore, the ions present in the solution after the dissolution of XeF₆ in HF are:
- Xenon pentafluoride ion: XeF₅⁺
- Bifluoride ion: HF₂⁻

5. **Conductivity of the Solution**:
- The solution is a good conductor of electricity due to the presence of these ions (XeF₅⁺ and HF₂⁻), which can move freely and carry charge.

6. **Conclusion**:
- The final conclusion is that the solution contains the ions XeF₅⁺ and HF₂⁻, which are responsible for its conductivity.

### Final Answer:
The good conducting solution formed when XeF₆ dissolves in anhydrous HF contains the ions **XeF₅⁺ and HF₂⁻**.

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