`SbF_(5)` reacts with `XeF_(4)` to form an adduct. The shapes of cation and anion in the adduct are respectively:

Options

A. square planar, trigonal bipyramidal
B. T-shaped, octahedral
C. square pyramidal, octahedral
D. square planar, octahedral

Explanation

To determine the shapes of the cation and anion formed when \( \text{SbF}_5 \) reacts with \( \text{XeF}_4 \), we can follow these steps:

### Step 1: Identify the Products
When \( \text{SbF}_5 \) reacts with \( \text{XeF}_4 \), it forms a cation and an anion:
- Cation: \( \text{XeF}_3^+ \)
- Anion: \( \text{SbF}_6^- \)

### Step 2: Determine the Shape of the Cation \( \text{XeF}_3^+ \)
1. **Count the Valence Electrons**:
- Xenon (Xe) has 8 valence electrons.
- Each fluorine (F) contributes 1 electron, and there are 3 fluorines.
- The cation \( \text{XeF}_3^+ \) has lost one electron, so the total is \( 8 + 3 - 1 = 10 \) valence electrons.

2. **Determine the Hybridization**:
- The central atom (Xe) is surrounded by 3 bonding pairs (from the 3 fluorine atoms) and has 2 lone pairs.
- This leads to a total of 5 electron pairs, indicating \( sp^3d \) hybridization.

3. **Shape**:
- With 3 bonding pairs and 2 lone pairs, the molecular geometry is T-shaped.

### Step 3: Determine the Shape of the Anion \( \text{SbF}_6^- \)
1. **Count the Valence Electrons**:
- Antimony (Sb) has 5 valence electrons.
- Each fluorine contributes 1 electron, and there are 6 fluorines.
- The anion \( \text{SbF}_6^- \) has gained one extra electron, so the total is \( 5 + 6 + 1 = 12 \) valence electrons.

2. **Determine the Hybridization**:
- The central atom (Sb) is surrounded by 6 bonding pairs (from the 6 fluorine atoms).
- This leads to a total of 6 electron pairs, indicating \( sp^3d^2 \) hybridization.

3. **Shape**:
- With 6 bonding pairs and no lone pairs, the molecular geometry is octahedral.

### Conclusion
Thus, the shapes of the cation and anion in the adduct formed from the reaction of \( \text{SbF}_5 \) and \( \text{XeF}_4 \) are:
- Cation \( \text{XeF}_3^+ \): T-shaped
- Anion \( \text{SbF}_6^- \): Octahedral

### Final Answer
The shapes of the cation and anion in the adduct are respectively T-shaped and octahedral.

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