Consider the followingg transformations:
(I) `XeF_(6)+NaF to Na^(+)[XeF_(7)]^(-)`
(II) `2PCl_(5)(s) to [PCl_(4)]^(+)[PCl_(6)]^(-)`
(III) `[Al(H_(2)O)_(6)]^(3+)+H_(2)O to [Al(H_(2)O)_(5)OH]^(2+)+H_(3)O^(+)`
Possible transformations are:

Options

A. I,II,III
B. I,III
C. I,II
D. II,III

Answer

To analyze the transformations given in the question, let's break down each transformation step by step.

### Transformation I:
**Reaction:** \( \text{XeF}_6 + \text{NaF} \rightarrow \text{Na}^+[\text{XeF}_7]^-\)

1. **Identify Reactants and Products:**
- Reactants: Xenon hexafluoride (\( \text{XeF}_6 \)) and sodium fluoride (\( \text{NaF} \)).
- Products: Sodium cation (\( \text{Na}^+ \)) and the anionic complex \( [\text{XeF}_7]^- \).

2. **Understanding the Formation of \( [\text{XeF}_7]^- \):**
- \( \text{XeF}_6 \) can accept a fluoride ion from \( \text{NaF} \).
- This results in the formation of \( [\text{XeF}_7]^- \) as xenon can expand its valence shell to accommodate more than 8 electrons.

3. **Geometry of \( [\text{XeF}_7]^- \):**
- The geometry of \( [\text{XeF}_7]^- \) is pentagonal bipyramidal.

4. **Conclusion:**
- This transformation is possible.

### Transformation II:
**Reaction:** \( 2\text{PCl}_5(s) \rightarrow [\text{PCl}_4]^+ + [\text{PCl}_6]^- \)

1. **Identify Reactants and Products:**
- Reactants: Two moles of phosphorus pentachloride (\( \text{PCl}_5 \)).
- Products: Cationic complex \( [\text{PCl}_4]^+ \) and anionic complex \( [\text{PCl}_6]^- \).

2. **Understanding the Reaction:**
- When two molecules of \( \text{PCl}_5 \) interact, they can exchange chlorine ligands.
- This results in the formation of \( [\text{PCl}_4]^+ \) (tetrahedral geometry) and \( [\text{PCl}_6]^- \) (octahedral geometry).

3. **Conclusion:**
- This transformation is also possible.

### Transformation III:
**Reaction:** \( [\text{Al(H}_2\text{O})_6]^{3+} + \text{H}_2\text{O} \rightarrow [\text{Al(H}_2\text{O})_5\text{OH}]^{2+} + \text{H}_3\text{O}^+ \)

1. **Identify Reactants and Products:**
- Reactants: Hexaaquaaluminum ion \( [\text{Al(H}_2\text{O})_6]^{3+} \) and water (\( \text{H}_2\text{O} \)).
- Products: Hydroxo complex \( [\text{Al(H}_2\text{O})_5\text{OH}]^{2+} \) and hydronium ion (\( \text{H}_3\text{O}^+ \)).

2. **Understanding the Reaction:**
- The water molecule can replace one of the \( \text{H}_2\text{O} \) ligands in the complex with a hydroxide ion (\( \text{OH}^- \)).
- This results in the formation of the new complex and the release of a hydronium ion.

3. **Geometry of the Complex:**
- The geometry of \( [\text{Al(H}_2\text{O})_5\text{OH}]^{2+} \) is octahedral.

4. **Conclusion:**
- This transformation is also possible.

### Final Conclusion:
All three transformations are possible.