Which of the following is an uncommon hydrolysis product of `XeF_(2) and XeF_(4)`?

Options

A. Xe
B. `XeO_(3)`
C. `HF`
D. `O_(2)`

Explanation

To solve the question of identifying the uncommon hydrolysis product of `XeF2` and `XeF4`, we will analyze the hydrolysis reactions of both compounds step by step.

### Step 1: Hydrolysis of Xenon Difluoride (XeF2)
1. **Reaction**: When `XeF2` undergoes hydrolysis, it reacts with water.
2. **Products**: The products formed are xenon gas (Xe) and hydrogen fluoride (HF).
3. **Balanced Equation**:
\[ 2 \, \text{XeF}_2 + 2 \, \text{H}_2\text{O} \rightarrow 2 \, \text{Xe} + 4 \, \text{HF} + \text{O}_2 \]

### Step 2: Hydrolysis of Xenon Tetrafluoride (XeF4)
1. **Reaction**: When `XeF4` undergoes hydrolysis, it also reacts with water.
2. **Products**: The products formed are xenon gas (Xe), xenon trioxide (XeO3), and hydrogen fluoride (HF).
3. **Balanced Equation**:
\[ 6 \, \text{XeF}_4 + 12 \, \text{H}_2\text{O} \rightarrow 4 \, \text{Xe} + 2 \, \text{XeO}_3 + 24 \, \text{HF} + 6 \, \text{O}_2 \]

### Step 3: Identify Common and Uncommon Products
1. **Common Products**:
- From both reactions, we can see that xenon (Xe) and hydrogen fluoride (HF) are produced in both hydrolysis reactions.
- Oxygen (O2) is also produced in both reactions.

2. **Uncommon Product**:
- The product `XeO3` is only formed during the hydrolysis of `XeF4` and not during the hydrolysis of `XeF2`. Therefore, it is considered the uncommon hydrolysis product.

### Conclusion
Based on the analysis, the uncommon hydrolysis product of `XeF2` and `XeF4` is **Xenon Trioxide (XeO3)**.

### Final Answer
The uncommon hydrolysis product of `XeF2` and `XeF4` is **Xenon O3 (XeO3)**.

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