Species having X-O-H linkage (X=non-metal with positive oxidation state) are called oxy acids and parent acid of a non-metal may exist in two form (a)-ic form of parent oxy acid (b)-us form parent oxy acid.
Q. Number of P-O bond(s) having bond order=2, in `P_(2)O_(6)^(4-)` ions is:

Options

A. 0
B. 2
C. 3
D. 6

Explanation

To solve the question regarding the number of P-O bonds with a bond order of 2 in the \( P_2O_6^{4-} \) ion, we can follow these steps:

### Step 1: Understand the structure of \( P_2O_6^{4-} \)
The ion \( P_2O_6^{4-} \) consists of two phosphorus (P) atoms and six oxygen (O) atoms. We need to visualize how these atoms are arranged and bonded.

**Hint:** Recall that the structure of oxyacids often involves distributing oxygen atoms around the central non-metal atoms (in this case, phosphorus).

### Step 2: Draw the Lewis structure
To draw the Lewis structure of \( P_2O_6^{4-} \):
- Start by connecting the phosphorus atoms to the oxygen atoms.
- Distribute the oxygen atoms around the phosphorus atoms to ensure that each phosphorus atom can form bonds with oxygen.
- Remember that phosphorus can expand its octet, allowing it to form more than four bonds.

**Hint:** Use the octet rule for oxygen and consider that phosphorus can have more than eight electrons around it.

### Step 3: Determine the types of bonds
In the Lewis structure, identify the types of bonds formed:
- Phosphorus can form double bonds with oxygen atoms, leading to P=O bonds.
- Some oxygen atoms may be connected through single bonds and carry negative charges.

**Hint:** Double bonds contribute to a bond order of 2, while single bonds contribute a bond order of 1.

### Step 4: Analyze the bond order
The bond order is defined as the number of bonding pairs of electrons between two atoms. For P-O bonds:
- Count the number of double bonds (P=O) in the structure.
- Note that if there are resonance structures, the bond order may not be a whole number.

**Hint:** Remember that resonance can affect the bond order, making it less than what you might expect from just counting bonds.

### Step 5: Conclusion on bond order
After analyzing the structure:
- In \( P_2O_6^{4-} \), it turns out that there are no P-O bonds with a bond order of exactly 2 due to the presence of resonance and the distribution of negative charges.

**Final Answer:** The number of P-O bonds having bond order = 2 in \( P_2O_6^{4-} \) is **0**.