`'X'+6H_(2)O to 'Y'+6HF`
`X+H_(2)O to 'Z'+2HF`
If 'X' is xenon hexafluoride than correct statement is:

Options

A. Compound 'Y' and 'Z' have same number of lone pair(s) at central atom
B. Both compound 'Y and 'Z' have same number of lone pair(s) at central atom
C. Z' is a partially hydrolysed product of compound 'X'
D. X' act as fluoride donor when it reacts with alkali metal fluoride.

Explanation

To solve the problem, we need to analyze the two reactions involving xenon hexafluoride (XeF6) and determine the correct statements about the products formed (Y and Z) from these reactions.

### Step-by-Step Solution:

1. **Identify 'X':**
- Given that 'X' is xenon hexafluoride (XeF6).

2. **Write the Reactions:**
- The first reaction is:
\[ \text{XeF}_6 + 6 \text{H}_2\text{O} \rightarrow \text{Y} + 6 \text{HF} \]
- The second reaction is:
\[ \text{XeF}_6 + \text{H}_2\text{O} \rightarrow \text{Z} + 2 \text{HF} \]

3. **Determine the Products 'Y' and 'Z':**
- For the first reaction, when XeF6 reacts with water, it undergoes hydrolysis to form:
\[ \text{Y} = \text{XeO}_3 + 6 \text{HF} \]
- For the second reaction, with partial hydrolysis, it forms:
\[ \text{Z} = \text{XeOF}_4 + 2 \text{HF} \]

4. **Analyze the Structures of 'Y' and 'Z':**
- **For Y (XeO3):**
- Xenon has 8 valence electrons.
- It forms three double bonds with oxygen (O), leading to a structure with one lone pair.
- Hybridization: sp³ (1 lone pair, 3 bond pairs).
- Geometry: Tetrahedral, Shape: Pyramidal.

- **For Z (XeOF4):**
- Xenon has 8 valence electrons.
- It forms four bonds with fluorine (F) and one double bond with oxygen (O), leading to a structure with one lone pair.
- Hybridization: sp³d (1 lone pair, 5 bond pairs).
- Geometry: Square pyramidal.

5. **Check the Statements:**
- **Statement 1:** Y and Z have the same number of lone pairs at the central atom.
- Both Y (XeO3) and Z (XeOF4) have 1 lone pair. **True.**
- **Statement 2:** Z is a partial hydrolysis product of compound X.
- Z (XeOF4) is indeed a product of the partial hydrolysis of XeF6. **True.**
- **Statement 3:** X acts as a fluoride donor when it reacts with alkali metal fluoride.
- When XeF6 reacts with alkali metal fluoride (like NaF), it accepts fluoride ions to form XeF8. **False.** (It acts as a fluoride acceptor, not a donor.)

6. **Conclusion:**
- The correct statements are 1 and 2.

### Final Answer:
The correct statements are:
1. Compound Y and Z have the same number of lone pairs at the central atom.
2. Z is a partial hydrolysis product of compound X.