In which of the following compound(s) terminal `(2C-2e^(-))` bond and bridge bonds are lying in same plane:

Options

A. `I_(2)Cl_(6)`
B. `Fe_(2)Cl_(4)`
C. Solid `BeCl_(2)`
D. `Ga_(2)H_(6)`

Explanation

To solve the question regarding which compounds have terminal (2C-2e^(-)) bonds and bridge bonds lying in the same plane, we will analyze each of the given compounds step by step.

### Step 1: Analyze I2Cl6
- **Structure**: I2Cl6 consists of two iodine atoms and six chlorine atoms. Each iodine atom forms bonds with three chlorine atoms.
- **Bonding**: The iodine atoms have lone pairs, and the chlorine atoms form both terminal and bridge bonds.
- **Plane Analysis**: In I2Cl6, both the terminal bonds (I-Cl) and the bridge bonds (Cl-Cl) are in the same plane.
- **Conclusion**: I2Cl6 has terminal and bridge bonds in the same plane.

### Step 2: Analyze Fe2Cl4
- **Structure**: Fe2Cl4 consists of two iron atoms and four chlorine atoms.
- **Bonding**: The iron atoms form coordinate bonds with the chlorine atoms.
- **Plane Analysis**: In Fe2Cl4, the terminal bonds (Fe-Cl) and the bridge bonds (Cl-Cl) are also in the same plane.
- **Conclusion**: Fe2Cl4 has terminal and bridge bonds in the same plane.

### Step 3: Analyze Solid BeCl2
- **Structure**: Solid BeCl2 consists of beryllium and chlorine atoms.
- **Bonding**: Beryllium forms bonds with chlorine atoms, but the structure is more complex.
- **Plane Analysis**: In solid BeCl2, the terminal bonds (Be-Cl) and the bridge bonds (Cl-Cl) do not lie in the same plane; they are in different planes.
- **Conclusion**: Solid BeCl2 does not have terminal and bridge bonds in the same plane.

### Step 4: Analyze Ga2H6
- **Structure**: Ga2H6 consists of gallium and hydrogen atoms.
- **Bonding**: Gallium forms bonds with hydrogen atoms, with some hydrogen acting as bridge bonds.
- **Plane Analysis**: In Ga2H6, the terminal bonds (Ga-H) and the bridge bonds are also not in the same plane; they are in different planes.
- **Conclusion**: Ga2H6 does not have terminal and bridge bonds in the same plane.

### Final Conclusion
The compounds that have terminal (2C-2e^(-)) bonds and bridge bonds lying in the same plane are:
- I2Cl6
- Fe2Cl4

Thus, the answer is **1 and 2**.

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