Borazine is called 'inorganic benzene' in view of its ring structure with alternate BH and NH groups. Which of the following statements is correct about borazine?

Options

A. Each B and N atom is `sp^(2)` hybridised
B. Borazine satisfied the `(4n+2)` Huckel's rule
C. Like organic benzene, borazine does not give addition product with HCl
D. Borazine contains dative `p pi-p pi` bond

Answer

To determine which statements about borazine are correct, we will analyze each statement based on the properties and structure of borazine.

### Step-by-Step Solution:

1. **Understanding the Structure of Borazine:**
- Borazine (B3N3H6) has a cyclic structure similar to benzene, with alternating boron (B) and nitrogen (N) atoms, and hydrogen (H) atoms attached to them.
- The structure can be represented as:
```
H H
\ /
B
/ \
N B
\ /
N
/ \
B H
\ /
H
```

2. **Analyzing the Hybridization:**
- Each boron and nitrogen atom in borazine is sp² hybridized.
- Hybridization can be determined by counting the number of sigma bonds and lone pairs. Each boron and nitrogen in borazine forms three sigma bonds (one with hydrogen and two with adjacent atoms), leading to an sp² hybridization.
- **Conclusion:** The first statement is correct: "Each boron and nitrogen atom is sp² hybridized."

3. **Applying Huckel's Rule:**
- Huckel's rule states that for a compound to be aromatic, it must have (4n + 2) π electrons, where n is a non-negative integer.
- In borazine, there are three double bonds (B=N), contributing a total of 6 π electrons.
- If we set n = 1, we get 4(1) + 2 = 6, which matches the number of π electrons in borazine.
- **Conclusion:** The second statement is correct: "Borazine satisfies the 4n + 2 Huckel's rule."

4. **Reactivity with HCl:**
- Unlike benzene, which does not react with HCl under normal conditions, borazine can react with HCl to form addition products.
- This is due to the presence of the nitrogen atoms, which can participate in reactions.
- **Conclusion:** The third statement is incorrect: "Like organic benzene, borazine does not give addition products with HCl."

5. **Presence of Dative Bonds:**
- Borazine contains dative (coordinate) bonds, particularly between boron and nitrogen. Boron has an empty p-orbital and can accept a pair of electrons from nitrogen, forming a dative bond.
- **Conclusion:** The fourth statement is correct: "Borazine contains dative p-pi-pi bonds."

### Final Conclusion:
- The correct statements about borazine are:
1. Each boron and nitrogen atom is sp² hybridized (Correct).
2. Borazine satisfies the 4n + 2 Huckel's rule (Correct).
3. Like organic benzene, borazine does not give addition products with HCl (Incorrect).
4. Borazine contains dative p-pi-pi bonds (Correct).

Thus, the correct options are the first, second, and fourth statements.