The reaction of sodium thiosulphate with `I_(2)` gives:

Options

A. sodium sulphite
B. sodium sulphate
C. sodium iodide
D. sodium tetrathionate

Answer

To solve the question regarding the reaction of sodium thiosulfate with iodine, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are sodium thiosulfate and iodine. The chemical formula for sodium thiosulfate is \( \text{Na}_2\text{S}_2\text{O}_3 \) and for iodine, it is \( \text{I}_2 \).

### Step 2: Write the Reaction
The reaction can be represented as:
\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow ? \]

### Step 3: Determine the Products
When sodium thiosulfate reacts with iodine, the products formed are sodium iodide (\( \text{NaI} \)) and sodium tetrathionate (\( \text{Na}_2\text{S}_4\text{O}_6 \)).

### Step 4: Write the Balanced Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. The balanced equation is:
\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow \text{Na}_2\text{S}_4\text{O}_6 + 2\text{NaI} \]

### Step 5: Identify the Correct Options
From the balanced equation, we can see that:
- Sodium iodide (\( \text{NaI} \)) is formed.
- Sodium tetrathionate (\( \text{Na}_2\text{S}_4\text{O}_6 \)) is also formed.

Thus, the correct products from the reaction of sodium thiosulfate with iodine are:
- Option C: Sodium iodide
- Option D: Sodium tetrathionate

### Final Answer
The reaction of sodium thiosulfate with iodine gives sodium iodide and sodium tetrathionate.

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