Home
Class 12
CHEMISTRY
Cl(2)O(6)+NaOH to ?...

`Cl_(2)O_(6)+NaOH to `?

A

`NaClO_(4)`

B

`NaOCl`

C

`NaClO_(2)`

D

`NaClO_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the reaction between dichlorine hexoxide (Cl₂O₆) and sodium hydroxide (NaOH), we will follow these steps: ### Step 1: Write the Reactants The reactants in this reaction are: - Dichlorine hexoxide: Cl₂O₆ - Sodium hydroxide: NaOH ### Step 2: Identify the Reaction Dichlorine hexoxide reacts with sodium hydroxide to form chlorate and perchlorate ions along with water. The general reaction can be represented as: \[ \text{Cl}_2\text{O}_6 + \text{NaOH} \rightarrow \text{NaClO}_3 + \text{NaClO}_4 + \text{H}_2\text{O} \] ### Step 3: Write the Products From the reaction, we can identify the products formed: - Sodium chlorate: NaClO₃ - Sodium perchlorate: NaClO₄ - Water: H₂O ### Step 4: Balance the Reaction To balance the reaction, we need to ensure that the number of atoms for each element is the same on both sides of the equation. 1. **Count the sodium atoms**: We have 2 sodium atoms from 2 NaOH, so we need to multiply NaOH by 2: \[ \text{Cl}_2\text{O}_6 + 2\text{NaOH} \rightarrow \text{NaClO}_3 + \text{NaClO}_4 + \text{H}_2\text{O} \] 2. **Now balance the equation**: - On the left side, we have 2 Na from 2 NaOH. - On the right side, we have 1 Na from NaClO₃ and 1 Na from NaClO₄, which gives us 2 Na in total. - The chlorine and oxygen atoms will also balance out as we have accounted for all products. ### Step 5: Final Balanced Equation The balanced equation is: \[ \text{Cl}_2\text{O}_6 + 2\text{NaOH} \rightarrow \text{NaClO}_3 + \text{NaClO}_4 + 2\text{H}_2\text{O} \] ### Step 6: Identify the Correct Options From the products formed: - NaClO₄ (sodium perchlorate) is formed. - NaClO₃ (sodium chlorate) is formed. - Water is also produced. Now, we can evaluate the options: - Option A: NaClO₄ - **Correct** - Option B: NaOCl - **Incorrect** - Option C: NaClO₂ - **Incorrect** - Option D: NaClO₃ - **Correct** ### Final Answer The correct products formed from the reaction of Cl₂O₆ and NaOH are: - NaClO₄ (sodium perchlorate) - NaClO₃ (sodium chlorate)
Promotional Banner

Topper's Solved these Questions

  • p-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise MATCH THE COLUMN|24 Videos
  • p-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise ASSERTION REASON TYPE QUESTIONS|24 Videos
  • p-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise LEVEL 3 (PASSAGE TYPE)|17 Videos
  • METALLURGY

    VK JAISWAL ENGLISH|Exercise ASSERTION-REASON TYPE QUESTIONS|29 Videos
  • PERIODIC PROPERTIES

    VK JAISWAL ENGLISH|Exercise MATCH THE COLUMN|11 Videos

Similar Questions

Explore conceptually related problems

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

In, Cl_(2)O_(6)(l)+HF to P+Q If H^(-) of acid HF attraches with Q, then correct option of hybridization of Cl-atom and angle OClO in the P and Q ions:

Solid Cl_(2)O_(6) is a covalnt compound.

Which of the following product(s) is/are obtained when Cl_(2)O_(6) reacts with KOH ?

Consider the following series of reactions : Cl_(2)+2NaOH to NaCl+NaClO+H_(2)O 3NaClO to 2NaCl+NaClO_(3) 4NaClO_(3) to 3NaClO_(4)+NaCl How much Cl_(2) is reqired to prepare 122.5 g of NaClO_(4) by above sequencial reactions ?

Consider the following series of reactions : Cl_(2)+2NaOH to NaCl+NaClO+H_(2)O 3NaClO to 2NaCl+NaClO_(3) 4NaClO_(3) to 3NaClO_(4)+NaCl How many moles of NaCl will be formed by using 1 mole Cl_(2) and other reagents in excess ?

underline(S)O_(2)Cl_(2)+H_(2)O to H_(2)SO_(4)+HCl

60ml of mixture of equal volumes of Cl_(2) and an oxide of chlorine, i.e., Cl_(2)O_(n) was heated and then cooled back to the original temperature. The resulting gas mixture was found to have volume of 75ml . On treatment with KOH solution, the volume contracted to 15ml . Assume that all measurements are made at the same temperature and pressure. Deduce the value of n in Cl_(2)O_(n) . The oxide of Cl_(2) n heating decomposes quantiatively to O_(2) and Cl_(2) .

The decompoistion of Cl_(2)O_(7) at 400 K in gas phase to Cl_(2) and O_(2) is a first order reaction. a. After 55 s at 400 K , the pressure of Cl_(2)O_(7) falls form 0.062 to 0.044 atm . Calculate k . b. Calculate the pressure of Cl_(2)O_(7) after 100 s of decompoistion.

VK JAISWAL ENGLISH-p-BLOCK ELEMENTS-ONE OR MORE ANSWERS IS/ARE CORRECT
  1. Which of the following statement(s) is/are correct?

    Text Solution

    |

  2. Which of the following statement is true about NO(2) and ClO(2)?

    Text Solution

    |

  3. Cl(2)O(6)+NaOH to ?

    Text Solution

    |

  4. Predict product(s) in the following reaction, Cl(2)+OH^(-) overset(h...

    Text Solution

    |

  5. In the isolation of fluorine a number of difficulties were encountered...

    Text Solution

    |

  6. Iodine is formed when potasium iodide reacts with:

    Text Solution

    |

  7. Available Cl2​ is liberated from bleaching powder when it :-

    Text Solution

    |

  8. Which reactions are used for the preparation of the halogen acid?

    Text Solution

    |

  9. Which of the following statement(s) is/are correct for halogens

    Text Solution

    |

  10. What are products in the following equation, S+OH^(-) to ?

    Text Solution

    |

  11. Correct statements about the hydrogen halides include that:

    Text Solution

    |

  12. Which of the following statement(s) is/are not correct?

    Text Solution

    |

  13. Which of the substances react with water?

    Text Solution

    |

  14. Which of the following substances are soluble in NaOH solution?

    Text Solution

    |

  15. Which of the following will give N(2) when heated?

    Text Solution

    |

  16. Which of the following will give NO(2) when heated?

    Text Solution

    |

  17. identify the correct statements:

    Text Solution

    |

  18. Select the correct statement(s):

    Text Solution

    |

  19. Which of the following gases on dissolution in water make the solution...

    Text Solution

    |

  20. Which of the following oxides is/are neutral?

    Text Solution

    |