Which of the following statement(s) is/are incorrect about borazine (inorganic benzene)?

Options

A. It contains `p pi-p pi` bond
B. it does not give addition product with HCl like organic benzene
C. each boron and nitrogen atom is `sp^(2)`-hybridised
D. Its disubstituted derivatives gives equal no. of ortho, meta and para devivatives like disubstituted organic benzene

Answer

To determine which statement(s) about borazine (inorganic benzene) are incorrect, we will analyze the properties and characteristics of borazine based on the provided information.

### Step-by-Step Solution:

1. **Identify the Chemical Formula and Structure**:
- Borazine has the chemical formula B3H6N3. It is structured similarly to benzene, with alternating boron (B) and nitrogen (N) atoms.

**Hint**: Remember that borazine is often referred to as "inorganic benzene" due to its structural similarity to benzene.

2. **Polarity of Borazine**:
- Borazine is a polar compound. This is due to the electronegativity difference between boron and nitrogen, which leads to a dipole moment in the molecule.

**Hint**: Consider the electronegativity values of boron and nitrogen to understand the polarity.

3. **Isoelectronic and Isoelectronic Nature**:
- Borazine is isoelectronic with benzene, meaning it has the same number of valence electrons as benzene (C6H6). This contributes to its structural similarity.

**Hint**: Isoelectronic species have similar electronic structures, which can affect their chemical behavior.

4. **Bond Lengths**:
- The bond lengths in borazine (B-N) are longer than the C-C bond lengths in benzene. The bond lengths indicate partial double bond character due to resonance.

**Hint**: Compare the bond lengths of B-N and C-C to understand their stability and reactivity.

5. **Reactivity with HCl**:
- Borazine does not react with HCl to form addition products like benzene does. This suggests that borazine is less reactive than benzene.

**Hint**: Think about the stability of the borazine structure and how it affects its reactivity.

6. **Formation of Derivatives**:
- Borazine does not produce equal amounts of meta and para derivatives upon substitution reactions, unlike benzene. This is due to the presence of both boron and nitrogen in the structure, which affects the distribution of substitution products.

**Hint**: Consider how the different substituents (B and N) influence the positions of new substituents in the reaction.

7. **Conclusion**:
- Based on the analysis:
- Borazine is polar (correct statement).
- Borazine does not give addition products with HCl (incorrect statement).
- Borazine does not yield equal numbers of meta and para derivatives (incorrect statement).
- Therefore, the incorrect statements about borazine are those regarding its reaction with HCl and the formation of derivatives.

### Final Answer:
The incorrect statements about borazine are:
1. It does not give addition products with HCl like organic benzene.
2. Its derivatives give equal numbers of meta and para derivatives like those of organic benzene.