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Oxy anion(s) containing (6,2) pair of eq...

Oxy anion(s) containing (6,2) pair of equivalent X-O linkaes (where X-central atom) is/are:

A

`S_(2)O_(8)^(2-)`

B

`P_(2)O_(6)^(4-)`

C

`P_(2)O_(7)^(4-)`

D

`P_(2)O_(8)^(4-)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding oxyanions containing (6,2) pairs of equivalent X-O linkages, we will analyze the given options step by step. ### Step 1: Understand the Question The question asks for oxyanions that have 6 pairs of equivalent X-O linkages and 2 pairs of equivalent exo linkages, where X is the central atom. ### Step 2: Analyze the Options We have four options to analyze: 1. Si2O8 2. P2O4O6^4- 3. P2O7^4- 4. P2O8^4- ### Step 3: Examine Each Oxyanion #### Option 1: Si2O8 - The structure of Si2O8 involves two silicon atoms bonded to eight oxygen atoms. - Due to resonance, we can determine that there are 6 equivalent Si-O bonds. - Additionally, we can identify 2 pairs of equivalent exo linkages. - **Conclusion**: This option satisfies the condition. #### Option 2: P2O4O6^4- - The structure involves two phosphorus atoms and multiple oxygen atoms. - Upon analysis, we find that there are no equivalent exo linkages present. - **Conclusion**: This option does not satisfy the condition. #### Option 3: P2O7^4- - The structure contains two phosphorus atoms linked to seven oxygen atoms. - There are 6 equivalent P-O bonds due to resonance. - Additionally, we can identify 2 pairs of equivalent exo linkages. - **Conclusion**: This option satisfies the condition. #### Option 4: P2O8^4- - The structure consists of two phosphorus atoms and eight oxygen atoms. - Similar to the previous options, we find 6 equivalent P-O bonds due to resonance. - There are also 2 pairs of equivalent exo linkages. - **Conclusion**: This option satisfies the condition. ### Step 4: Final Conclusion Based on the analysis: - **Correct Answers**: Options 1 (Si2O8), 3 (P2O7^4-), and 4 (P2O8^4-) contain the required (6,2) pairs of equivalent X-O linkages.
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Consider the following oxyanions: PO_(4)^(3-),P_(2)O_(6)^(4-),SO_(4)^(2-),MnO_(4)^(-),CrO_(4)^(2-),S_(2)O_(5)^(2-),S_(2)O_(7)^(2-) and find the value of R+Q-P where P-number of oxy anions having three equivalent X-O bonds per central atom Q=number of oxy anions having two equivalent X-O bonds per central atom. R=Number of oxy anions having four equivalent X-O bonds per central atom.

Species having X-O-H linkage (X=non-metal with positive oxidation state) are called oxy acids and parent acid of a non-metal may exist in two form (a)-ic form of parent oxy acid (b)-us form parent oxy acid. Q. X-O-X bond (where X=central atom) is not present in species.

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